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Solving this system yields (verify)     are the nonzero vectors of the form
Thus the eigenvectors corresponding to

is a basis for the eigenspace corresponding to .

Notice that the zero vector is in every eigenspace, although it isn't an eigenvector.

Powers of a Matrix

Once the eigenvalues and eigenvectors of a matrix A are found, it is a simple matter to find the eigenvalues and eigenvectors of
any positive integer power of A; for example, if is an eigenvalue of A and x is a corresponding eigenvector, then

which shows that is an eigenvalue of and that x is a corresponding eigenvector. In general, we have the following result.

THEOREM 7.1.3

  If k is a positive integer, is an eigenvalue of a matrix A, and x is a corresponding eigenvector, then is an eigenvalue of
      and x is a corresponding eigenvector.

EXAMPLE 6 Using Theorem 7.1.3
In Example 5 we showed that the eigenvalues of

are and , so from Theorem 7.1.3, both           and are eigenvalues of . We also showed that

are eigenvectors of A corresponding to the eigenvalue , so from Theorem 7.1.3, they are also eigenvectors of

corresponding to  . Similarly, the eigenvector

of A corresponding to the eigenvalue    is also an eigenvector of corresponding to  .

Eigenvalues and Invertibility
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