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Let be the vector space of functions with continuous first derivatives on , let
be the vector space of all real-valued functions defined on , and let be the
differentiation transformation . The kernel of D is the set of functions in V with derivative zero. From calculus,
this is the set of constant functions on .
Properties of Kernel and Range
In all of the preceding examples, and turned out to be subspaces. In Examples Example 2, Example 3, and
Example 5 they were either the zero subspace or the entire vector space. In Example 4 the kernel was a line through the origin,
and the range was a plane through the origin, both of which are subspaces of . All of this is not accidental; it is a consequence
of the following general result.
THEOREM 8.2.1
If is linear transformation, then
(a) The kernel of T is a subspace of V.
(b) The range of T is a subspace of W.
Proof (a) To Show that is a subspace, we must show that it contains at least one vector and is closed under addition and
scalar multiplication. By part (a) of Theorem 8.1.1, the vector 0 is in , so this set contains at least one vector. Let and
be vectors in , and let k be any scalar. Then
so is in . Also,
so is in .
Proof (b) Since , there is at least one vector in . Let and be vectors in the range of T, and let k be any
are in the range of T; that is, we must find vectors and in V
scalar. To prove this part, we must show that and
such that and .
Since and are in the range of T, there are vectors and in V such that and . Let
and . Then
and
which completes the proof.
In Section 5.6 we defined the rank of a matrix to be the dimension of its column (or row) space and the nullity to be the
dimension of its nullspace. We now extend these definitions to general linear transformations.

