Page 137 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

129

3.

ก. !8 ,.

.' %
!!

& E
9
g
(
'
.
'
.V ! E = 5 V ( % ก( ก ,.

.')
g
R
P-P
L

9
- ,
ก. !8 ,.

.' %
!!

& E
g
C
&9 E ก C +
+;
C ก !ก (3.11)
2
g
2P
2
2
C N
2 2 S S ;
C N S = C N P , C =
S
P
P
N 2 P
, C = C , C = C = 70 pF, N = N = 5 T, N = N = 2 T;
P 2P S 2 P 1 S 3
×
C N 2 3 70 10 − 12 ( ) 2 2
2
C 2P = = = 11.2 pF
N 2 ( ) 5 2
1
R
&9 E ก R +
+;
R ก !ก (3.10)
L g L LP
2
Z P = Z S , Z = Z N P ;
S
P
N 2 P N 2 S N 2 S
Ω
, Z = R LP , Z = R = 75 , N = N = 5 T, N = N = 2 T;
S
P
3
P
1
S
L
R N 2 1 75 ( ) 5 2
L
R LP = 2 = 2 = 468.75 Ω
N ( ) 2
3
C
&9 E ก C +
+;
C ก !ก (3.11)
1P
1
g
1
C N 2 S ;
2
2
S
C N = C N , C =
S S P P P 2
N P
, C = C 1P , C = C = 600 pF, N = N = 5 T, N = N = 10 T;
P
2
S
S
2
P
1
×
10
C N 2 2 600 10 − 12 ( ) 2
1
C 1P = 2 = 2 = 2.4 nF
N ( ) 5
1

!!

&9 E
g
E g L 1
N
1
Ω
C = 11.2 pF, R = 468.75 , C = 2.4 nF, L = 100.925 nH;
2P LP 1P 1
+ 3.10 !!

&9 E
g
ก

ก
ก