Page 138 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

130

3.

1
ก !ก (3.1b) F =
R
2π LC
, L = L = 100.925 nH
1
×
C = C + C = ( 2.4 10 − 9 + 11.2 10 − 12 ) = 2.4112 10 − 9 = 2,411.2 pF
×
×
1P 2P
1
F =
R
2π L C + C )
1 ( 1P 2P
1
F =
R
×
×
×
( 2 3.14 ) ( 100.9 10 − 9 × 2,411.2 10 − 12 )
F = 10.208 MHz
R
" F = == = 10.208 MHz
R
(
'
.
'
1
ก !ก (3.2) B =
W
π
2 CR
×
R LP g 468.75 75
R
Ω
, C = C + C = 2, 411.2 pF, R = ( R R ) = = = 64.655 ;
1P 2P LP g
+
R + R 468.75 75
LP g
1 1
B = =
W 2 R C + C 2P ) 2 3.14 64.655 2, 411.2 10 − 12
π
×
×
×
×
( 1P
B = 1.021 MHz
W
" B = == = 1.021 MHz
W
.V ! E = 5 V ( % ก( ก ,.

.')
g
P-P
R
L
E N
ก !ก (3.8) E = P S
S
N P
, E = V RL , N = N = 5 T, N = N = 2 T;
S
1
S
P
3
×
E R 5 468.75
g LP
E = = = 4.310 V
P
p-p
R +
+
g R LP 75 468.75
×
E N 3 4.310 2 1.724 V
P
V = = =
R L p-p
N
1 5
" V R L = == = 1.724 V
p-p

3.5

@A

+ "
#
*

$
ก + 3.11 ! 8 2( %
:-
ก

ก
ก