Page 175 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

167
4.

4.1.2 ก
ก#

2

ก 1 4.4 ก.--
2 ก 750 kHz 1.5 MHz E
i

200 mV peak
4.1.2.1 ก
(

) C
CM
1
$% C .5( L (ก -ก .--# (4%
ก
CM 43
L 13 ( N 23 + N 33 ) 2
ก
ก (4.4) L =
43 2
N 13
1
ก
ก (4.5a) C =
CM 2
π
L ( 2 F ( )
43 R L 43 )
*& 4.5 (
C
CM
×
L 13 ( N 23 + N 33 ) 2 1.3 10 − 6 (89 70+ ) 2
+ , ก
ก (4.4) L 43 = =
N 2 ( ) 7 2
13
L = 670.72 µH
43
1
ก
ก (4.5a) C =
CM 2
π
L ( 2 F ( )
43 R L 43 )
$% F = 750 kHz, L = 670.72 µH;
R (L 43 ) 43
1 67.207 pF
C = =
CM 2
×
×
×
×
670.72 10 − 6 ( 2 3.14 750 10 3 )
67.207 pF 5
0 ' 68 pF
= == = 68 pF /
ก
* C CM

+V
V max +V V
T
3 750 kHz max
0 π 2π 3π t
0
T π 2π 3π
T N L
− V L 13 23 23 − V
N 13
N 33 L 33
E
g
750 kHz
1.5 MHz
L 23 , N 23
L 13 , N 13
L 33 , N 33 D 1 ,D 2 #1N60 t = 0,V = 0.35 V,I = 5 mA,V = 20 V,PIV = 50 V;
R
rr
F
F
T L = 1.3 µH,N = 7 T,L = 213 µH,N = 89 T,L = 130 µH,N = 70 T;
3 13 13 23 23 33 33

1 4.4 . %
2 $% , 4%$ % , ก ก.--
ก

ก
ก