Page 176 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง
P. 176
168
4.
4.1.2.2 ก
(
) I #% I
D
D
1
2
E N 23 V FD 1
i
ก
ก (4.2) I D 1 = − )
N
1
1
13 ( R + R L ) ( R + R L
E N 33 V FD
i
ก
ก (4.3) I = − 2
D 2 N 13 ( R + R L ) ( R + R L )
2
2
*& 4.6 (
I .5( I
D 1 D 2
E N 23 V FD
i
+ , ก
ก (4.2) I D = − 1
1
N 13 ( R + R L ) ( R + R L )
1
1
×
200 10 − 3 × 89 0.35
I D = − = 1.461 mA peak
(
1
×
+
×
+
7 500 1 10 3 ) ( 500 1 10 3 )
E N 33 V FD
i
ก
ก (4.3) I D = − 2
2
N 13 ( R + R L ) ( R + R L )
2
2
×
200 10 − 3 × 70 0.35
I D = − = 1.10 mA peak
(
+
2
×
+
×
7 500 1 10 3 ) ( 500 1 10 3 )
* I = = = = 1.461 mA , I = = = = 1.10 mA ;
D 1 peak D 2 peak
4.1.2.3 ก
%0 ก T
3
( , IFT(.ก
5! ) # + 3
4.1.2.4 ก
(
) V #% V
π ππ
π
π
π ππ
π
o (0- ) o ππ π
( -2 )
E N V FD
ก
ก (4.6) V = I R = R L i 23 − 1
π
o (0- ) D 1 L
R +
R +
N 13 ( 1 R L ) ( 1 R L )
E N V FD
ก
ก (4.7) V o π π = I D R = R L i 33 − 2
( -2 )
L
2
N 13 ( R + R L ) ( R + R L )
2
2
*& 4.7 (
V o (0- ) .5(V o ( -2 )
π
π
π
E N V FD
+ , ก
ก (4.6) V o (0- ) = I R = R L i 23 − 1
π
L
D
R +
R +
1
N 13 ( 1 R L ) ( 1 R L )
×
×
3
V o (0- ) = I R = 1.461 10 − 3 × 1 10 = 1.461 V peak
π
D
L
1
E N V FD
ก
ก (4.7) V o π π = I D R = R L i 33 − 2
L
( -2 )
2
N 13 ( R + R L ) ( R + R L )
2
2
3
×
×
V o ( -2 ) = I D 2 R = 1.10 10 − 3 × 1 10 = 1.10 V peak
π
π
L
* V o (0- ) = = = = 1.461 V peak ,V o ππ π = = = = 1.10 V peak ;
π
π
π ππ
π
π π π
( -2 )
ก
ก
ก

