Page 82 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง
P. 82

74
               2.




                X (%	 ก ! R      
,      	  F   "  ก  ก
                 C T       FH                    H
                                                              X  =  R
                                          C T  FH
                                  1
               (
-     ก   X C T  =  2 F Cπ  H T

                   "                               1  = R
                                               FH
                                     π
                                    2 F C
                                        H T
                                                  1
                  
 $
                                      F =                                                                           (2.17)
                                          H
                                              2 Rπ  FH C T
                                             r bb′  b′  C = C b e ′ + C b c ′  (1 g R+  m out )
                                                     T

                                                                   m b e ′
                                                   C T  r b e ′  V b e ′  g V
                            E g


                                                                                   Z out

                                       ,%   2.15         ,      	  F     A
                                                                  H      V (F H  )

                                           C =  C b e ′ +  C b c ′  (1 g R+  m out )
                                            T
                                    r bb′                                        R FH 1  R FH
                               B         b′                  C               r bb′
                        R g                r          g V
                                      C T  b e ′       m b e ′
                                                                   R g  R BB       r b e ′    C
                       E         R BB                                                          T
                        g
                                                 E

                                               R R                        r R
                                             
                                                                               ′
                                                                  r
                                       R   =    g BB  +  r bb′ ,R  =  ( b e ′    R  ) =  b e FH 1  ;
                                        FH 1         )       FH        FH 1    +    )
                                               R +
                                                                             r
                                              ( g  R BB                  ( b e ′  R FH 1
                                             
                                          ,%   2.16         ก  ,      	  R
                                                                         FH
                                                        ก  ,      	     R  #  (,5
 	      " 
% 
%  ( 
  	 C
                                                       FH                               T
                
  ,%   2.16
                                                     R R        R r  +  R r  +  R R
                                              
                                                              
                                       R FH 1 =  r   bb′  +  g BB   =  g bb′  BB bb′  g BB
                                                   ( R +  R BB  )    ( R +  R BB )
                                                              
                                              
                                                      g
                                                                          g
                                                             r R   1
                                                              ′
                                                             b e FH
                                                            R  =  (r     R  ) =
                                         FH    b e ′  FH 1           )
                                                            r
                                                           ( b e ′  +  R FH 1
                                                   r b e ′  ( R r  +  R r  +  R R  )
                                                                BB bb′
                                                         g bb′
                                                                        g BB
                                        R FH  =
                                              R r   +  R r  +  R r  +  R r  +  R R
                                               g b e ′
                                                               g bb′
                                                                      BB bb′
                                                      BB b e ′
                                                                              g BB
                                                                            ก         	
    
    ก  
  ก
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