Page 84 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง
P. 84

76
               2.



                                                      r         E r R
                                                
                                                              
                                                                      ′
                                         V b e ′  =  I b   b e ′    =  g b e BB
                                                  (1 J r Cω+  b e T  )    a
                                                         ′
                                                           V =
                                                  ′
                                               m b e out
                                           o  g V Z
                                                V o    g Z  r R
                                                              ′
                                                        m out b e BB
                                      A V  (F  )  = −  = −
                                          H     E g         a
                                1               r b e ′  ( R r  +  R r  +  R R BB )
                                                     g bb′
                                                            BB bb′
                                                                    g
               (
-     ก  Cω  T  =  , R FH  =                                  ;
                              R FH         R r  +  R r  +  R r  +  R r  +  R R
                                                           g bb′
                                            g b e ′
                                                   BB b e ′
                                                                  BB bb′
                                                                          g BB
                                                1    R r  +  R r  +  R r  +  R r  +  R R
                                                      g b e ′
                                                                            BB bb′
                                                                     g bb′
                                                             BB b e ′
                                                                                    g BB
                                                              C =  =
                                        ω
                                           T
                                              R FH        r b e ′  ( R r  +  R r  +  R R  )
                                                                      BB bb′
                                                               g bb′
                                                                              g BB
                %
 	  C    
 a
                      ω
                         T
                          g Z   r R
                                 ′
                           m out b e BB
                A V  (F  )  = −
                    H
                               a
                                                         g Z   r R
                                                                ′
                                                          m out b e BB
                A V  (F H  )  = −                                                                  }
                                                            +
                                             +
                              r
                                                   r
                           R
                                                                                      BB bb′
                                                                g b e ′
                                                                               g bb′
                                                                       BB b e ′
                                                                                              g BB
                          { g  ( bb′  +  r b e ′  +  R BB  ) R BB  ( bb′  +  r b e ′  ) JR r  +  R r  +  R r  +  R r  +  R R
                                                      g Z   r R
                                                             ′
                      = −                              m out b e BB
                          R g  (r bb′  +  r b e ′  +  R BB ) R+  BB  (r bb′  +  r b e ′  ) JR+  g  (r bb′  +  r b e ′  +  R BB  ) R+  BB  (r bb′  +  r b e ′  )
                                        g Z   r R BB
                                          m out b e ′
                A V  (F H  )  = −
                              r
                           R
                                                   r
                          { g  ( bb′  +  r b e ′  +  R BB  ) R+  BB  ( bb′  +  r b e ′  )}(1 J+  ) 1
                                              g Z   r R
                                                     ′
                                               m out b e BB
                A     = −
                 V  (F H  )                                                  1
                           R  (r  +  r  +  R  ) R+  (r  +  r  )} ( ) 1  2  +  ( ) 1  2  tan − 1
                          { g  bb′  b e ′  BB   BB  bb′  b e ′
                                                                             1
                                          g Z   r R
                                                 ′
                                           m out b e BB
                A V  (F H  )  = −
                                                                  45
                                                   r
                               r
                           R
                          { g  ( bb′  +  r b e ′  +  R BB ) R+  BB  ( bb′  +  r b e ′  )} 2
                                                            )
                                                      (0.707 g Z   r R     − 45
                                                                     ′
                                                               m out b e BB
                                      A V  (F H  )  = −                         )
                                                                        r
                                                   r
                                                          R g  ( bb′  +  r b e ′  +  R BB  ) R+  BB  ( bb′  +  r b e ′
               (
-     ก   Z in    =               R BB
                        Z R +  Z in  ) { g  ( bb′  +  r b e ′  +  R BB ) R+  BB  ( bb′  +  r b e ′  )}
                                         r
                                                            r
                                     R
                          ( g
                         i
                                                                      −
                                                V o   (0.707 g Z  r                 Z in
                                                                       45
                                                           ) m out b e ′
                                      A V (F H  )  = −  = −               ×  R +
                                                           E g  Z i          g  Z in
                                   V o    g Z  r       Z in
                                           m out b e ′
               (
-     ก  A V (F  )  = −  = −      ×
                            Mid
                                   E g       Z i    R +  Z in
                                                      g
                                                V o                  −
                                      A V  (F  )  = −  =  (0.707 A  (F  )  45
                                                          ) V
                  
 $
                                 H  E g  Mid                                              (2.18)
                                                                            ก         	
    
    ก  
  ก
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