Page 83 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

75
2.

,
2.9 ก ,% 2.1 , F
H
1
- .
ก ก (2.17) F =
H
π
2 R FH T
C
 R R   75 7,500 
×


g BB

* % R FH 1 =  ) + r bb′  =  + ) + 2 = 76.257 Ω
  ( R + R BB    (75 7,500 
g
×
r R 1 588.64 76.257 69.767 ;
′
b e FH
Ω
R FH = = = 67.511 , R out = Ω
r
( b e ′ + R FH 1 ) (588.64 76.257+ )
C b c ′ = C ob = 1 pF
×
g m 169.883 10 − 3 − 12
×
C b e ′ = − C ob = − 1 10 = 3.508 pF
2 F T 2 3.14 6 10 9
π
×
×
×
×
×
C = C b e ′ + C b c ′ (1 g R ) 3.508 10 − 12 + × − 12 { 1+ ( 169.883 10 − 3 × 69.767 )}
=
+
1 10
T
m out
C = 16.360 pF
T
1 1
F = =
H 2 Rπ FH T 2 3.14 67.511 16.360 10 − 12
×
×
×
×
C
F = 144.172 MHz
H
F == = 144.172 MHz
=
H
2.1.4.2 ก
)
#
*
A V (F H )

-

"
.
V E
A V (F H ) o g
"
ก ,% 2.15 2.16 ( - E
(% ก ! F % . X (% ก ! R " ก
g H C T FH
  r   

E = I R + I R r + b e ′  
g i g i  BB  bb′
ω
+
b e T  
   1 J r C
′
   r    

E = I i  R +  R BB  r bb′ + b e ′   

g
g
+
ω
     1 J r C 
b e T  
′
 R g ( bb′ + r b e ′ + R BB ) R+ BB ( bb′ + r b e ′ )
r
r


a =  
+ J r C ( R R + R r + r R ) 
ω
′
 b e T g BB g bb′ bb′ BB 
a
E = I
g i )
ω
r
′
( bb′ + r b e ′ + R BB ) + J r C ( R BB + r bb′
b e T
ω
+
E g ( { r bb′ + r b e ′ + R BB ) J r C ( R BB + r bb′ )}
′
b e T
I =
i
a )
′
i BB
I = I R (1 J r C+ ω b e T
b )}
( { R BB + r bb′ + r b e ′ ) J r C+ ω b e T ( R BB + r bb′
′
E R (1 J r C+ ω ′ )
I = g BB b e T
b
a
ก

ก
ก