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Mathematics Term 1  STPM  Answers

                      1
                (b)  S  =    3 1 –  1  1  2 4 ; lim S  = S =   1     6  –11        1  –17  –5
                              n
                   n  6     16  n → ∞    n  ∞    6             DA =  1  4  2  2  , DB =  1  2  –2  6 2
               17.  (a)  138                                         –7  0        –3  7   –7
                (b)   1   (10  – 1);   1   (10 n + 1  – 9n – 10)    4.  (a)   –4 2  (b)  –7 –4
                      n
                   9       81                                     1 10 9 2            1  7  12 2
               18.  (a)   676  (b)  493    (c)   1168
                   2475         825           1665               (c)   1  9 1  –1  4 2 2  (d)  1 –8  –2  –4 2
                                                                                       8
                                                                                          15
                                                                      10
                                                                                              6
                        1
               19.  (b)  u n + 1  =  u n  (c)  S  =  lim  S  =   3 2    5.  x = 2, y = 4, z = 1, w = 3
                        2
                                       ∞
                                              n
                                          n → ∞
                       2
               20.   5   x +  15  x  +  65  x 3
                2   4     8                                   7.  a = 1, b = –3
               21.  (a)  752                                       50  –50  100        0  –15  –30
                                                                           0
                                                                       0
                                                                   0
                                  1
                       1
               22.  1 + apx +  a p(p – 1)x  +  a p(p – 1)(p – 2)x ; 3    8.  (a)   1 10  –10  20 2  (b)  1  0 0  –15  –30 2
                         2
                               2
                                    3
                       2
                                                                                           30
                                                                                               60
                                  6
                    8
                           4
                 3
                  –   , –   ; |x| ,   .

                 4  3      3                                     (c)  (57)         (d)  (5)
                              2 1249
                       1
                           1
               23.  n = 4; 1 –   x –   x ;                         12  –6  36
                       2   8    200                              (e)   1  2  –1  6 2     (f)  (17)
               24.  p = 3, q = 2, n = 8                            –2  1  –6
                     1
                                                                                        6
                                                                                           8
               25.  1 + x +   x 2                             9.  (a)   1  38  27 2  (b)  1 11  16  16 2
                     2
                                                                                              24
               26.   1 1  4                                        –16  –4              1  –1  12
                   1 2 , 0.98952
                6 n
                        2

               27.  (a)   1   n(28n  – 1)   (b)   1   ,   4    10.  (a)   –1  0  31  (b)  1 –1  –4  –12 2
                                                                                        2
                                                                                               24
                                                                                           8
                   3                   999 37                     1 –10  –4  104 2     –3  –12  –36
                                          6
                                                 6
               28.  (a)  167 167; 111 445   (b)  A =   13 , B = 1;   13                 2   2
                     1
                                              2
                                         4
               29.  (a)  1 +  x –   3  x 2  (b)  20x  + 160x  + 64; 1364       (c)   1 –11 –11 2  (d)  1  –5  –5 2
                     4   32                                        –18 –18             –32  –32
               30.  –   1   –   2   +   3  2  ; 0, 5, 6; 3r + 1 + (–1) r + 1  11  4  –135  2  8   24
                 1 + x  1 – x  (1 – x)
                                                                 (e)   1  –22  –8  270  2  (f)  1  –5  –20  –60  2
                         2  (1 – x
               31.  (a)  S   = 2x 3  n – 1 ) 4                      33  12  –405       –32  –128  –384
                   n – 1    1 – x
                   15                                       Exercise 3.2
                (b)  ∑ (2r – 1)3  = 602 654 097                                               2  2
                           r
                   r = 1                                      1.  (a)  9    (b)  2        (c)  x  + y  – 2
                   14                                         2.  (a)  0    (b)  0        (c)  –14
                   ∑ (2r + 1)3 r + 2  = 1 807 962 291
                   r = 1                                      3.  (a)  x(x – 1)   (b)  8a(1 – 2a)  (c)  axy(2 – ay)
                                                              4.  (a)  –3   (b)  3        (c)  3
               Chapter  3  Matrices                                             5
                                                              5.  (a)  –96   (b)  192     (c)  75
             Exercise 3.1                                     6.  (a)   18    (b)  2      (c)  –  1
                    3
                                                                  5
                                        0
                                              3
                                           1
                                                                                              2
               1.  (a)   1 –6  12  0 6 2  (b)  1 –3 –5  –1 2    7.  (a)  0, –9   (b)  0, –2   (c)  –3, 0, 2
                       0
                                           5
                                        1
                (c)   1  1 1  3 5  –3 2         (d)   1 –5 –5  3 1 2  Exercise 3.3
                         3
                                                                                          5
                    2
                        11
                                                                      1
                (e)   1 –13  –15  9 1 2                       1.  (a)   1 0 –1 2   (b)  1 –3  –3 2
                                                                                       2
                                                                   1
                                                                   7
                                                               (c)   1 –4  –5 2    (d)  1 3 –2 2
                                                                                       7 –5
                                                                      3
                                        16
                       24
                           24
                    24
                                               16
                                           16
               2.  (a)   1 33  –6  –39 2  (b)  1 18  5  –31 2                          –2 –1
                    30  18  9           9  –2  28              (e)  None           (f)   1  3  2  2
                                                                                        1
                    3
                               2
                                   2
               3.  A  =  1 –5 8 5 2  , AB =  1 –1  13  8 3 2   (g)  None           (h)  1  —  0  2
                 2
                                                                                        3
                                                                                             1
                           2
                                                                                             2
                BC =  1  3 4  –3  –2 2  , BD =  1 –10 –1 2         0 –1         3  1    0  – —  3 –2
                                    2
                                        2
                        16
                   1  5  1  3 2    1  5  10 2                 2.  (a)   1 1  4  2  (b)  1 2  1 2  (c)  1 0  2  2
                C  =  –2  16  –5  , CD =  11  –1
                 2
                                                                                        –1
                                                                   –1
                    –4  2  –3       –1  –7                    3.  (a)  A B         (b)  BA
                                                               (c)  B              (d)  A BA
                                                                                       –1
             280
       Answers STPM Math T S1.indd   280                                                               3/28/18   4:25 PM
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