Page 5 - Focus TG4 KSSM (Physics) Terbitan Penerbitan Pelangi Sdn Bhd
P. 5

Physics  Form 4  Chapter 2 Force and Motion I

                                                      Displacement and velocity
                      3.  (a)  Displacement by an object is the distance travelled by the object in a
                            specific direction.                                      N
                         (b)  It is the distance travelled by the object from its initial position to its   W  E  Delima
                            final position in a straight line.
                          (c)  For the car travelling  from Delima  to Mengkibol,  the displacement is   S  45°
                            determined  by measuring  the length  of the straight line  connecting   800 m
                            Delima to Mengkibol in the direction of Mengkibol from Delima.
                          (d)  Hence from Figure 2.4, its displacement is given by the following,  Mengkibol  800 m
                            Magnitude of the displacement                                Figure 2.4
                                  2
                            =  800  + 800 2
                            = 1 131 m
                            Its direction is south-west of Delima (or S45°W of Delima)
                           (e)  Hence, displacement is a vector quantity.                                    Chapter
                      4.  (a)  Velocity is defined as the rate of change of displacement.
                           (b)  In the case of the car travelling from Delima to Mengkibol, the average velocity, v, is given by:
                                                          Displacement,s                                    2
                                                      v  =   Time taken, t

                                                          1 131 m
                                                        =   120 s   = 9.4 m s –1
                           (c)  Velocity is a vector quantity.


               EXAMPLE  2.1                                    EXAMPLE  2.2

                A cow walked along a curved path from P to Q,   An athlete runs from the   P           Q
                which is 70 m away from P. Q lies to the south-west   starting point O to P which is   100 M
                of P. The distance travelled by the cow is 240 m   100 m north of O. After that he
                and the time taken is 160 s.                    runs to point Q which is 100 m   100 M  N
                                          U                     east of P. The total time taken
                                                                is 25 seconds.            O

                                                                What is the (a) distance,  (b)   Figure 2.6
                                P
                                                                average speed, (c) displacement,  and (d) average
                                                                velocity traveled by the athlete?
                         Q
                                 Figure 2.5                     Solution
                Calculate the  (a)  average speed, and          (a)  Total distance traveled
                            (b)  average velocity                  = 100 + 100 = 200 m
                of the cow moving from P to Q.
                                                                (b)  Average speed
                Solution                                             Total distance  200
                                                                                             –1
                Total distance travelled = 240 m                   =   Total time   =   25   = 8 m s
                Displacement = 70 m                             (c)  Displacement O
                Time taken = 160 s                                 =  100  + 100 2
                                                                         2
                                    Total distance travelled
                (a)  Average speed  =                              = 100 2 m
                                         Time taken
                                    240 m                       (d)  Average velocity
                                  =        = 1.5 m s –1
                                    160 s
                                      Displacement  70 m           =  Displacement    =   100 2   = 4 2  m s –1
                (b)  Average velocity  =          =                    Total time      25
                                       Time taken   160 s
                                                                                    o
                                             –1
                                    =  0.44 m s  in the south-     in the direction N45 E from O.
                                      west direction of P
                                                                                                    21





       02 FOC PHYSICS F4 3P.indd   21                                                                29/01/2020   1:39 PM
   1   2   3   4   5   6   7   8   9   10