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Physics  Form 4  Chapter 2 Force and Motion I

             Analysis of Motion
                                                             EXAMPLE  2.6
               1.  A ticker timer is an apparatus used to study
                 the motion of an object within a short period   A trolley pulled a ticker tape through a ticker timer
                 of time.                                     while moving down an inclined plane. Figure 2.17
                                                              shows the ticker tape produced.
               2.  Figure 2.15 shows a ticker timer connected to
                 an a.c. power supply.

                                                                                12 cm
                              Power supply                                    Figure 2.17
                              a.c.12 V    POWER SUPPLY
                                        FUSE   10  12  Volts  1
                                         8  plus
                                        O  6                  Determine the average velocity of the trolley.
                    Ticker timer         4  AC 2  0  0
                                        I  OVLD  DC
                                                              Solution
                  Ticker
                  tape                                        Displacement = 12 cm
                                                              There are 10 spaces between the dots,
        Chapter
       2                         Vibrating bar                Therefore, time taken = 10 × 0.02 = 0.2 s
                                                                              Displacement
                                                              Average velocity =
                                                                               Time taken
                         Figure 2.15  Ticker timer                       =   12 cm   = 60 cm s –1
                                                                            0.2 s
               3.  A carbonised ticker tape is passed through the
                 ticker timer and is pulled by a moving object.  EXAMPLE  2.7
                                                              A trolley is pushed   Length/cm
               4.  When  the a.c.  power supply is switched on,   to move up the slope    4.5
                 the vibrating bar vibrates 50 times per second   of an inclined plane.   4.0
                 (following the frequency of the power supply   Figure 2.18 shows the   3.5
                                                                                    3.0
                 which is 50 Hz). Each time the vibrating bar     arrangement of the   2.5
                 hits the tape, a dot is produced on the tape.  ticker tapes. Each strip   2.0
                                                                                    1.5
               5.  The period of time between 2 adjacent dots is   consists of 5 ticks or 0.1   1.0
                                                                                    0.5
                 known as 1 tick.                             second. Determine the     0.2 0.4 0.6 0.8  t /s
                                                              acceleration of the trolley.  Figure 2.18
                                                              Solution
                                                              Average initial velocity of the trolley,
                                                                 4.5 cm
                        Dot      1 tick                       u  =      = 45.0 cm s –1
                  Figure 2.16   1 tick for carbonised ticker tape  0.1 s
                                                              Average final velocity of the trolley,
                                                                 1.5 cm
               6.  A ticker timer can be used to determine    v =   0.1 s   = 15.0 cm s –1
                 (a)  time,                                   Time taken, t  = (4 – 1) × 0.1
                 (b)  displacement,                                       = 0.3 s
                 (c)  average velocity,                       Therefore, acceleration, a =   v – u
                 (d)  acceleration, and                                                 t
                 (e)  type of motion                                                =  15.0 – 45.0
                 of an object.                                                           0.3
                                                                                    = –100 cm s –2
                                                              Because  the  acceleration  has a negative  value,
                                                              therefore the trolley experienced a deceleration
                                                              with the magnitude of 100.0 cm s .
                                                                                          –2


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