Page 22 - Steady Mate Tg1 - Book A
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Matematik  Tingkatan 1  Bab 1 Nombor Nisbah


                                                                KANDUNGAN
                                          Praktis Berfomat                        PT3



                1.  Antara nombor berikut, yang manakah bukan nombor        Jawapan / Answer:
                   nisbah?                                                       8            7
                   Which of the following numbers is not a rational number?  (i)   5   = 1.6  ;  –2  = –2.875
                                                                                              8
                                                                                   7
                   A  –16               C  2.4                              (ii)  –2  , –2.65 , 0 ,   8   , 1.8
                                                                                   8           5
                       2                     8
                   B                    D  –
                       0                     3
                                                                        (b)  Rajah di bawah menunjukkan kad-kad bernombor.
                                 5                                          The diagram shows numbered cards.
                2.              2       – 4     2.6
                                 9
                   Antara operasi berikut, yang manakah  menghasilkan        –6  1    3.6   1.4   –2    1    – 4.8   – 0.5
                   nilai yang terbesar?                                         4                    8
                   Which of the following operations gives the largest value?     Berdasarkan rajah di atas,
                   A  +, +              C  –, +                             Based on the diagram,
                   B  +, –              D  –, –                             (i)  cari nilai hasil darab terbesar yang mungkin
                                                                                bagi dua nombor
                3.  Pada ruang jawapan, isi petak kosong dengan nombor          find the largest possible product of two numbers
                   yang betul.                                                                      [2 markah / 2 marks]
                   In the answer space, fill in the boxes with the correct numbers.  (ii)  cari nilai beza terkecil yang mungkin antara
                                              [4 markah / 4 marks]              dua nombor.
                   Jawapan / Answer:                                            find the smallest possible difference between two
                                                                                numbers.
                   3   21
                      –    ÷ 0.7                                                                    [2 markah / 2 marks]
                   5   25                                                   Jawapan / Answer:
                     3   21     7
                   =    –    ÷                                                     1
                     5   25    10                                           (i)  – 6  × (– 4.8) = 30
                                                                                   4
                     3   21    10                                                  1
                   =    –    ×                                              (ii)  – 6  – 3.6 = – 6.25 – 3.6 = –9.85
                     5   25     7                                                  4
                     3     6                                            (c)  Suleiman mempunyai wang simpanan sebanyak
                   =    –                                                                           3
                     5     5                                                RM208. Dia menderma        daripada wang
                                                                                                   10
                        3                                                   simpanannya  kepada  Tabung  COVID-19  dan
                   =  –
                        5                                                   kemudian, dia membeli sebotol pensanitasi tangan
                                                                            yang berharga RM74.20. Hitung baki wang yang
                                                                            Suleiman ada.
                4.  (a)  Berikut ialah satu senarai nombor.                                                        3
                                                                            Suleiman has a savings of  RM208. He donates
                       The following is a list of numbers.                                                        10
                                                                            of his savings to COVID-19 fund and then, he buys a
                                 8   , 1.8 , –2  , 0 , –2.65                bottle of hand sanitizer that costs RM74.20. Calculate
                                           7
                                 5         8
                                                                            the remaining money Suleiman has.
                                                                                                    [3 markah / 3 marks]
                       (i)  Tukar pecahan kepada perpuluhan.                Jawapan / Answer:
                           Convert the fractions to decimals.               Baki wang yang Suleiman ada
                                              [2 markah / 2 marks]          Remaining money Suleiman has
                       (ii)  Susun nombor-nombor itu mengikut tertib          7

                           menaik.                                          =  10  × 208 – 74.2
                           Arrange the numbers in ascending order.          = 145.6 – 74.2
                                               [1 markah / 1 mark]
                                                                            = RM71.40


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