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Matematik  Tingkatan 1   Bab 13 Teorem Pythagoras

                  C    Cari nilai x bagi setiap segi tiga bersudut tegak yang berikut.    TP 3   ARAS R
                      Find the value of x in each of the following right-angled triangles.

                    Contoh                           1.                                2.
                                                                 x cm                                     x cm
                                                                                               12 cm
                             x cm                                        8 cm
                                      3 cm
                                                                6 cm                                    16 cm
                               4 cm                     2   2   2                         2    2    2
                                                       x  = 6  + 8                       x  = 12  + 16
                  x   = 3  + 4 2                         = 36 + 64                         = 144 + 256
                       2
                   2
                    = 9 + 16                             = 100                             = 400
                    = 25
                                                       x  =  100                         x  =  400
                  x  =  25                               = 10                              = 20
                    = 5


                  D    Cari nilai y bagi setiap segi tiga bersudut tegak yang berikut. Berikan jawapan kepada dua tempat perpuluhan jika
                      perlu.    TP 3   ARAS R
                      Find the value of y in each of the following right-angled triangles. Give your answer in two decimal places if necessary.

                    Contoh                           1.           26 cm                2.

                                                                                                         12 cm
                                   y cm                                 24 cm                  y cm
                    5 cm                                      y cm
                                                                                                       8 cm
                                                         2
                                                             2
                                                                                               2
                                                                                           2
                                13 cm                  26 = y  + 24 2                    12  = y  + 8 2
                                                         2
                                                              2
                                                         y  = 26  – 24 2                   y  = 12  – 8 2
                                                                                                2
                                                                                           2
                 13  = y  + 5 2                            = 676 – 576
                       2
                   2
                   2
                        2
                   y  = 13  – 5 2                          = 100                             = 144 – 64
                     = 169 – 25                                                              = 80
                     = 144                               y  =  100                         y  =  80
                   y  =  144 = 12                          = 10                              = 8.94
                  E    Hitung nilai x dan y dalam setiap rajah berikut. Berikan jawapan dalam dua tempat perpuluhan jika perlu.    TP 3
                      Calculate the values of x and y in each of the following diagrams. Give your answer in two decimal places if necessary.    ARAS S
                    Contoh                                            1.                  P
                                               P                                                17 cm
                                                                                       8 cm             Q
                                                                                      10 cm   x cm
                                     20 cm      x cm                                 S     R
                                            y cm
                                                                                                  24 cm
                                                                                     y cm
                                Q       R  9 cm  S
                                       16 cm                                              T
                                                                         Dalam / In ΔPRQ        Dalam / In ΔQTS
                 Dalam / In ΔPQS        Dalam / In ΔPRS                  x  = 17  – 8 2         QS  = 15 + 10
                                                                               2
                                                                          2
                                         2
                  2
                                             2
                       2
                 x  = 20  – 16 2        y   = 9  + 12 2                    = 289 – 64              = 25 cm
                   = 400 – 256             = 81 + 144                      = 225                 2     2    2
                   = 144                   = 225                                                y   = 25  – 24
                                                                         x  =  225                 = 625 – 576
                 x  =  144              y  =  225                          = 15                    = 49
                   = 12                    = 15
                                                                                                y  =  49   = 7
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