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Matematik   Tingkatan 2  Bab 2
               6.  Selesaikan setiap yang berikut.   SP 2.1.4
                  Solve each of the following.
                  (a)  Shao Kang membeli p buah buku latihan dengan  (b)  Seetha  mempunyai  sebidang  tanah  berbentuk
                      harga RM(q + 1) sebuah dan q buah buku rujukan   segi  empat  tepat  seperti  yang  ditunjukkan
                      dengan harga RM(p + 2) sebuah. Dia membayar      dalam rajah di bawah. Cari luas, dalam m , tanah
                                                                                                            2
                      dengan  harga  RM5pq.  Hitung  baki  wang  yang   itu.    TP4
                      diterimanya, dalam RM.                           Seetha  has a piece of rectangular  land as shown in the
                                                                                                2
                      Shao Kang bought p exercises book at RM(q + 1) each and   diagram below. Find the area, in m , of the land.
                      q reference books at RM(p + 2) each. He paid at the price of
                      RM5pq. Calculate the balance he received, in RM.    TP4
                      Baki/ Balance                                                              (4x + 3) m
                      = 5pq – p(q + 1) – q(p + 2)
                      = 5pq – pq – p – pq – 2q                                        (7x + 5) m
                                                                                              2
                      = 3pq – p – 2q                                   Luas tanah / Area of land (m )
                                                                       = (7x + 5)(4x + 3)
                      Baki wang/ Balance                               = 28x + 21x + 20x + 15
                                                                            2
                      = RM(3pq – p – 2q)
                                                                       = 28x + 41x + 15
                                                                            2



                  (c)  Kelab Matematik sebuah sekolah ingin menjual roti sandwic sempena Hari Kantin. Mereka memerlukan
                      30 tin sardin dan 15 buku roti. Rajah di bawah menunjukkan harga sardin dan roti di dua buah pasar
                      raya.     TP5    KBAT  Menganalisis
                      Mathematics Club of a school wants to sell sandwhich during Canteen’s Day. They need 30 cans of sardine and 15 loaves of bread.
                      The diagram below shows the prices of sardine and bread in two supermarkets.

                               Pasar Raya Ekstra                                Pasar Raya Bajet



                                                                      SARDIN SARDIN SARDIN
                           SARDIN                                      SARDIN SARDIN SARDIN
                                                                                                        4
                          RMs              RM(r + 1)                       RM4s                 RM –– (r + 1)

                                                                                                      5

                      Hitung kerugian yang dialami jika mereka membeli barang di pasaraya yang menawarkan harga yang
                      lebih mahal. Nyatakan jawapan dalam sebutan s dan r.
                      Calculate the loss incurred if they bought the items in the supermarket that offers more expensive price. State the answer in terms of
                      s and r.


                      Jumlah bayaran di Pasar Raya Ekstra/ Total payment in Pasar Raya Ekstra
                      = 30s + 15(r + 1)
                      = 30s + 15r + 15

                      Jumlah bayaran di Pasar Raya Bajet/ Total payment in Pasar Raya Bajet
                                    4
                              
                      = 5(4s) +  15 ×  (r + 1) 
                                    5
                                               6 tin/ cans
                      = 20s + 12(r + 1)       30 tin/ cans  = 5
                      = 20s + 12r + 12
                                                                         Pasar Raya Ekstra menawarkan harga yang lebih
                      Kerugian/ Loss = (30s + 15r + 15) – (20s + 12r + 12)  mahal berbanding Pasar Raya Bajet.
                                                                         Pasar Raya Ekstra offers more expensive price compared
                                   = 30s + 15r + 15 – 20s – 12r – 12     to Pasar Raya Bajet.
                                   = 10s + 3r + 3






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