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Matematik Tambahan Tingkatan 5 Bab 1 Sukatan Membulat
5. Tentukan sudut tercangkum, q dalam radian, di pusat bulatan dengan diberikan jejari bulatan, j dan panjang
lengkok, s bagi setiap bulatan yang berikut. TP 3
Determine the angle subtended, q in radians, at the centre of the circle given the radius, j and the arc length, s for each of the
1 following circles.
BAB CONTOH (a) 7.2 cm
6.1 cm O
P 4.4 cm
O
Q
9.8 cm 7.2
(2π – q) =
Penerbitan Pelangi Sdn. Bhd.
Penyelesaian: 6.1
q rad panjang lengkok, s / arc length, s q = 5.1 rad
=
2π rad 2πj
Ini boleh dringkaskan kepada
This can be simplified into
s
q =
j
(2π – q) = 9.8
4.4
q = 4.06 rad
(b) 4.8 cm (c)
=
=
O 3.2 cm O
1.8 cm
2.8 cm
4.8 2.8
(2π – q) = (2π – 2q) =
3.2 1.8
q = 4.78 rad q = 2.36 rad
(d) (e) 11.4 cm
=
2.5 cm
O O
=
3.2 cm
=
6.3 cm 8.2 cm
2πj = 6.3 + 8.2 + 11.4
(2π – q) = 3.2 j = 4.12 cm
3 2.5 11.4
q = 2.44 rad q = 4.12
= 2.77 rad
6
01 M&M Mate T Tg5.indd 6 09/12/2022 12:20 PM

