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Additional Mathematics  SPM  Chapter  2 Quadratic Functions
                    Number line method                       Table method

                                  x = –2,                                Range of values of x
                     x = –4,  [–3(–2) – 5](–2 + 3) ≥ 0  x = 0,
                 [–3(–4) – 5](–4 + 3) ≤ 0  [–3(0) – 5](0 + 3) ≤ 0                   5     5
                                                                      x  –3 –3  x  –  3  x  –  3
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                                                   x
                         –          +         –           (–3x – 5)     +       +       –
                             –3          –  5
                                          3      5        (x + 3)       –       +       +
          Form 4     The range of values of x is –3  x  –   .    (–3x – 5)(x + 3)  –  +  –  5
                                                 3
                                                             The range of values of x is –3  x  –   .
                                                                                          3

                   2.2     Types of Roots of Quadratic Equations



                                                                             2
                                                         2
                 Discriminant       b  – 4ac  0        b  – 4ac = 0        b  – 4ac < 0
                                     2
                                  Two different real   Two equal real roots   No real roots
                 Type of roots
                                       roots
                Example 6                                Example 7
                Determine the type of roots for each of the   The quadratic equation –5x  – x = 2 – m
                                                                                2
                following quadratic equations.           has two different real roots. Find the range
                (a)  x – 4x + 3 = 0                      of values of m.
                     2
                (b)  –4x + 20x – 25 = 0
                       2
                (c)  2x  + 4x + 5 = 0                      Solution
                      2
                                                         –5x  – x – 2 + m = 0
                                                            2
                  Solution                               a = –5, b = –1, c = –2 + m
                (a)  x – 4x + 3 = 0                                 b  – 4ac  0
                     2
                                                                     2
                    a = 1, b = –4, c = 3                  (–1)  – 4(–5)(–2 + m)  0
                                                             2
                    b  – 4ac = (–4)  – 4(1)(3)                  1 – 40 + 20m  0
                                2
                     2
                           = 4  0                                      20m  39
                    ∴ The equation has two different real                 m   39
                      roots.                                                  20
                       2
                (b)  –4x + 20x – 25 = 0
                    a = –4, b = 20, c = –25              Example 8
                                                                               2
                    b  – 4ac = 20  –4(–4)(–25)           The  quadratic  equation  hx  +  kx – 7 = 0
                     2
                               2
                           = 0                           has two equal real roots. Express h in terms
                    ∴  The equation has two equal real   of k.
                      roots.
                (c)  2x  + 4x + 5 = 0                      Solution
                      2
                    a = 2, b = 4, c = 5                      b  – 4ac = 0
                                                              2
                                                          2
                    b  – 4ac = 4  – 4(2)(5)               k  – 4(h)(–7) = 0
                              2
                     2
                                                              2
                           = –24  0                         k  + 28h = 0  k 2
                    ∴ The equation has no real roots.              h = –   28
                                                     18
         02 Ranger Add Mathematics Tg4.indd   18                                            25/02/2022   9:10 AM
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