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Operations on Whole Numbers

           Find the L.C.M of 28, 30, and 35

             2    28,   30,   35       2 is the least common prime factor of 28 and 30.
             5    14,   15,   35       5 is the least common prime factor of 15 and 35.
             7    14,   3,    7        7 is the least prime factor of 14 and 7.
                  2,    3,    1

           ? L.C.M. = 2 × 5 × 7 × 2 × 3 = 420

                                        Workedout examples


           Example 1:  Write the sets of a few multiples of 6, 9, and 12. Make a set of their
                        common multiples and find their L.C.M.
           Solution:
           Here, M   = {6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, …}
                    (6)
                  M   = {9, 18, 27, 36, 45, 54, 63, 72, 81, 90, …}
                    (9)
                  M (12)  = {12, 24, 36, 48, 60, 72, 84, 96, 108, 120, …}
           Now,   M ˆ M ˆ M          = (36, 72, …)
                    (6)    (9)   (12)
           ? L.C.M. of 6, 9, and 12 is 36.
           Example 2:  Three measuring rods are 30 cm, 45 cm, and 60 cm long. Find the
                        shortest length of cloth which can be measured exactly by any one
                        of these rods.
           Solution:
           Here, the shortest length of the cloth is the L.C.M. of 30 cm, 45 cm, and 60 cm.

             2    30,   45,   60
             3    15,   45,   30
             5    5,    15,   10
                  1,    3,    2

           ? L.C.M. = 2 × 3 × 5 × 3 × 2 = 180
           Hence, the required shortest length of the cloth is 180 cm.
           Example 3:  Find the least number which leaves a remainder 7 when it is divided
                        by any one of the numbers 20, 30, and 40.
           Solution:
           Here, the least number divisible by 20, 30, and 40 is their L.C.M. Then, the required
           least number = (L.C.M. of 20, 30, 40) + 7.

             2    20,   30,   40
             2    10,   15,   20
             5    5,    15,   10
                  1,    3,    2
           ? L.C.M. = 2 × 2 × 5 × 3 × 2 = 120
           Hence, the required least number = 120 + 7 = 127.

           Vedanta Excel in Mathematics - Book 7   40    Approved by Curriculum Development Centre, Sanothimi, Bhaktapur
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