Page 15 - Integration Problems
P. 15
Example 3:
Perform the following integration,
2
∫ 2
0 + 4 + 29
Whenever you see an integral with a quadratic
expression in the denominator then you need to
express it in terms of sum of the squares.
Let,
2
2
2
+ 4 + 29 = ( + ) +
Expand the brackets,
2
2
2
2
+ 4 + 29 = + 2 + +
Equate coefficients,
4 = 2
2
2
29 = +
= 2
2
29 = 4 +
2
= 29 − 4 = 25
The denominator becomes,
11
