Page 158 - Matematik Tambahan Tingkatan 4 KSSM

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Sebutan ke-n, JANJANG Sebutan ke-n,
n – 1
T = a + (n – 1)d r��u� T = ar
n
n r��u�
Janjang
Janjang
Geometri
Aritmetik Hasil tambah n sebutan
pertama,
Hasil tambah n
sebutan pertama, a��i��s� a(r – 1)
n
n S = , r ≠ 1(|r| > 1)
S = [2a + (n – 1)d] Hasil tambah n r – 1
n 2
ketakterhinggaan, a(1 – r )
n
Penyelesaian S = a , |r| < 1 S = 1 – r , r ≠ 1(|r| < 1)
n
∞
masalah 1 – r

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R
R
R
R
R
R
R
R
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
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S
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S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
U
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
U
U
U
U
U
U
T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T T
TULIS JURNAL ANDA
U
U
U
U
U
U
U
U
U
U
U
U
U
U
R
R
R
R
R
R
R
R
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R
R
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R
R
R
R
R
R
R
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R
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R
R
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R
R
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R
R
R
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R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
R
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R
R
R
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R
R
R
R
R
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R
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R
R
R
R
R
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R
R
R
R
U
U
U
U
U
U
U
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U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
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U
U
U
U
U
U
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U
U
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U
U
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U
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U
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U
U
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U
U
S
S
U
S
S
S
U
U
U
U
U
U
U
U
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U
U
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U
U
U
U
U
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U
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U
U
S
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S
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S
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S
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L
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S
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L
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S
S
S
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S
S
S
S
S
S
S
S
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
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U
U
U
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U
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U
U
U
U
U
U
U
U
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U
U
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U
U
U
U
U
U
U
U
U
U
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U
U
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U
U
U
U
U
U
U
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U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
L
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
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S
L
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L
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L
L
L
L
L
L
L
L
S
S
S
S
S
S
S
S
S
L
S
S
S
L
L
L
L
L
L
L
L
L
L
L
L
L
L
I
I
I
L
L
I
I
L
L
L
L
L
L
L
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
S
L
S
S
S
S
S
S
S
S
S
L
L
L
L
L
L
L
L
L
L
L
L
L
L
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L
L
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L
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L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
I
I
I
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
L
I
I
L
I
I
I
L
L
L
L
L
L
I
I
I
I
I
I
BAB 5

Bina satu info grafik berkaitan perbezaan antara janjang aritmetik dengan janjang geometri.

Kemudian, fikirkan satu situasi dalam kehidupan harian anda yang mengaplikasikan kedua-dua
janjang ini dan selesaikannya.
U
U
U
U
U
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
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H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
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I
I
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
H
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
I
I
I
I
I
I
I
I
I
I
I
I
I
I
U
U
U
U
U
U
U
I
I
I
I
I
I
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
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I
I
I
I
I
I
I
I
I
I
I
I
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I
I
I
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I
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I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
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I
I
I
I
I
I
I
I
I
I
I
I
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I
I
I
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I
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I
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I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
I
I
I
U
U
U
I
I
I
I
I
I
I
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
T
T
T
T
T
T
T
T
T
T
T
T
T
T
H
H
H
H
H
H
H
T
T
T
H
T
T
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
I
I
I
U
U
U
U
U
U
U
I
I
I
I
I
I
I
I
I
I
I
I
I
I
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
U
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
I
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
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N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
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A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
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A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
A
N
A
A
A
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
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A
A
A
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A
A
A
A
A
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A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L L
LATIHAN PENGUKUHAN
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
N
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
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A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
A
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
T
T
T
T
T
T
T
T
T
T
T
H
H
H
H
H
T
T
H
H
H
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
T
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
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H
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H
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H
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H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
H
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1. –2x – 1, 3x + 2 dan 9x + 3 ialah tiga sebutan berturutan bagi janjang aritmetik. Cari TP1
(a) beza sepunya,
(b) sebutan pertama jika 3x + 2 ialah sebutan ketiga.
2. Sebutan ke-9 suatu janjang aritmetik ialah 21 + 3p dan hasil tambah tiga sebutan pertama
ialah 9p. Cari beza sepunya. TP2
3.
3. Rajah menunjukkan tiga buah silinder dengan keadaan isi padu
setiap silinder disusun mengikut janjang aritmetik. Hasil
tambah isi padu silinder pertama dan silinder ketiga ialah
3
3
24 cm dan isi padu silinder kelima ialah 36 cm . TP3
(a) Cari isi padu silinder terkecil.
(b) Hitung hasil tambah isi padu bagi 9 buah silinder yang pertama.
4.
4. Sebutan ke-3 bagi suatu janjang geometri ialah 30 dan hasil tambah sebutan ke-3 dan ke-4
ialah 45. Cari TP2
(a) sebutan pertama dan nisbah sepunya,
(b) hasil tambah ketakterhinggaan.
150