Page 6 - Grab A+ Kertas Model SPM Matematik
P. 6
Jawapan Lengkap (Kertas1)
JAWAPAN / ANSWERS Complete Answers (Paper 1)
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Kertas Model 1/ Model Paper 1 3 × 1 – 2:
12x + 15y – (8x + 15y) = 60 – 54
Kertas 1/ Paper 1 12x + 15y – 8x – 15y = 6
4x = 6
1. A 2. B 3. D 4. B 5. D 6
6. A 7. C 8. B 9. C 10. C x = —
4
11. D 12. B 13. A 14. A 15. D x = 1.50
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16. B 17. A 18. A 19. C 20. A Gantikan x = 1.50 ke dalam 1,
21. D 22. B 23. C 24. B 25. D Substitute x = 1.50 into 1,
26. C 27. A 28. D 29. C 30. A 4(1.50) + 5y = 20
31. D 32. D 33. B 34. C 35. D 6 + 5y = 20
36. D 37. B 38. A 39. B 40. D 5y = 20 – 6
14
y = —–
Kertas 2/ Paper 2 5
y = 2.80
Bahagian A/ Section A ∴ Harga sebungkus nasi lemak ialah RM1.50 dan harga
1. (a)
sebungkus mi goreng ialah RM2.80.
The price of a pack of nasi lemak is RM1.50 and the price of
a pack of fried mee is RM2.80.
3. (a) (i) Benar/ True
(ii) Palsu/ False
(b) 3x ≠ 15
(c) (i) Daripada rajah,
From the diagram,
3 = 2 + 2 1 – 1
4 = 2 + 2 2 – 1
θ 6 = 2 + 2 3 – 1
10 = 2 + 2 4 – 1
58 cm ∴ 2 + 2 n – 1 , n = 1, 2, 3, 4, ...
58
(b) kos θ/ cos θ = —–– (ii) 2 + 2 n – 1 = 258
140
58
1
θ = kos / cos —–– 2 2 n – 1 = 258 – 2
–1
–1
140
= 256
2
n – 1
θ = 65° 32ʹ 2 n – 1 = 2
8
Sudut di antara satah dengan tangga dan lantai ialah n – 1 = 8
65° 32ʹ. n = 9
The angle between the plane with the ladder and the floor ∴ Terdapat 9 baris susunan duit syiling.
is 65° 32ʹ. There are 9 rows of coin arrangement.
130
(c) sin θ = —–– 4. (a)
140
–1 130
1
θ = sin —–– 2 Jarak (km)
Distance (km)
140
θ = 68° 13ʹ 50
Sudut di antara satah dengan tangga dan lantai yang perlu 40
ditambah 30
The angle between the plane with the ladder and the floor 20
that need to be added 10
= 68° 13ʹ – 65° 32ʹ Masa (minit)
O 10 20 30 40 50 60 70 80 90 100 110120 Time (minute)
= 2° 41ʹ
2. Katakan/ Let (b) (i) Laju/ Speed
20 – 0
x = harga sebungkus nasi lemak = —–———
25
the price of a pack of nasi lemak —– – 0
y = harga sebungkus mi goreng 60
–1
the price of a pack of fried mee = 48 km j / km h –1
4x + 5y = 20 ..................1 (ii) Tempoh masa Armel berhenti di Taman Beverly
Duration of time Armel stopped at Taman Beverly
8x + 15y = 54 ................2
= 45 – 25
= 20 minit/ minutes
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