Page 9 - Grab A+ Kertas Model SPM Matematik

5p 9 2p – 4
—– + — , ——––
3 3 5 20. A Bulan Januari Mac Ogos
5(5p + 9) , 3(2p – 4) Month January March August
25p + 45 , 6p – 12
25p – 6p , –12 – 45 Kos
19p , –57 perubatan 12 000 8 500 22 000
(RM)
57
p , – —– Medical
19
p , –3 cost (RM)
Boleh
6hk + 2h 2 9hk + 3h k
2
3
2
14. A ————– ÷ ———–—– menuntut
3k 6kh Ya Tidak Ya
2h(3k + h) 6kh 2 pampasan Yes No Yes
2
= ——–——– × ———–—– Can make
3k
3hk(3k + h)
2
4h a claim
= —–
3k Pampasan
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yang
15. D 6p + 4q + 3 = 166q + 3 diperoleh 12 000 – 10 000 22 000 – 10 000
3
6p = 166q + 3 – 4q – 3 (RM) = 2 000 – = 12 000
3
6p = 162q Claim
3
162q received
p = —–—
3
6 (RM)
p = 27q
3
3
p = ABBB Jumlah pampasan yang diperoleh oleh Sharon
27q
q
p = 3AB Amount of claim obtained by Sharon
3
= RM2 000 + RM12 000
= RM14 000
16. B (3x – 2y) + x(2x + y)
2
= 9x – 12xy + 4y + 2x + xy
2
2
2
= 11x – 11xy + 4y 2 21. D Pintasan-y/ y-intercept = 16
2
16 – 2x = 0
3
16 = 2x 3
17. A F 16
x = —–
3
2
x = 8
3
x = 2
Pintasan-x/ x-intercept = 2
Graf berbentuk/ The shape of graph is .
Q P Jadi/ Hence, a = –2 , 0
∠FPQ Maka/ Thus, y = 16 – 2x 3
∴ ∠FPQ

22. B Pintasan-y/ y-intercept = 3
1
18. A —x + 3 = 0
R 2 1
1 S T —x = –3
2
2 3 4 x = –6
A B C D
Pintasan-x/ x-intercept = –6
1
m = —, maka graf berbentuk
2
1
m = —, thus the shape of graph is
2
R  S ʹ  T ʹ
= {1, 2, 3}  {1, 3, 4} {1, 2} 23. C Persamaan PQ ialah/ Equation of PQ is
= {1} 2
Maka, rantau A. y = —x + 4 ......... 1
3
Therefore, region A. Gantikan y = 0 ke dalam 1,
Substitue y = 0 into 1,
2
19. C ξ = {28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41} —x + 4 = 0
P = {28, 31, 33, 35, 37, 39, 40} 3 2
P ʹ = {29, 30, 32, 34, 36, 38, 41} —x = –4
3
n(Pʹ) = 7 x = –6
Pintasan-x ialah –6.
The x-intercept is –6.
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