Page 6 - Modul A+1 Kimia Tingkatan 5

9. Langkah 2 hingga 8 diulang dengan menggantikan kepingan zink, Zn dan larutan zink sulfat, ZnSO
4
1.0 mol dm di dalam pasu berliang dengan:
–3
–3
Steps 2 to 8 are repeated by replacing zinc, Zn plate and 1.0 mol dm zinc sulphate, ZnSO solution in the porous pot with:
4
(a) paku besi, Fe dan larutan ferum(II) sulfat, FeSO 1.0 mol dm .
–3
4
Bab 1 (b) pita magnesium, Mg dan larutan magnesium sulfat, MgSO 1.0 mol dm .
iron nail and 1.0 mol dm iron(II) sulphate, FeSO solution.
–3
4
–3
4
–3
magnesium, Mg ribbon and 1.0 mol dm magnesium sulphate, MgSO solution.
4
Keputusan/ Results: TP 3
Pasangan logam Voltan (V) Terminal negatif (anod) Terminal positif (katod)
Set
Pair of metals Voltage (V) Negative terminal (anod) Positive terminal (katod)
I Zink dan kuprum Zink Kuprum
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Zinc and copper 1.1 Zinc Copper
II Ferum dan kuprum Ferum Kuprum
Iron and copper 0.7 Iron Copper
III Magnesium dan kuprum 2.7 Magnesium Kuprum
Magnesium and copper Magnesium Copper
Kesimpulan/ Conclusion: TP 5

Hipotesis diterima . Pasangan logam dengan perbezaan nilai keupayaan elektrod piawai lebih besar akan
menghasilkan nilai voltan yang lebih besar .

The hypothesis is accepted . Pairs of metal with greater difference of standard electrode potential value will
produce greater voltage .

Perbincangan/ Discussion: TP 5
1. Set 1 : Zink dan kuprum/ Set I: Zinc and copper

Elektrod/ Electrodes Zink/ Zinc Kuprum/ Copper
Pengoksidaan atau penurunan Pengoksidaan/ Oxidation Penurunan/ Reduction
Oxidation or reduction
Setengah persamaan tindak balas Zn ➝ Zn + 2e – Cu + 2e ➝ Cu
2+
–
2+
Reaction half-equations
Persamaan ion keseluruhan Zn + Cu ➝ Zn + Cu
2+
2+
Overall ionic equation
Notasi sel/ Cell notation Zn(p/s) | Zn (ak/aq) || Cu (ak/aq) | Cu(p/s)
2+
2+
E 0 = E 0 – E 0
Nilai voltan sel (V) sel/cell katod/cathode anod/anode
Voltage value of the cell (V) = (+0.34 V) – (–0.76 V)
= 1.10 V
2. Set II: Ferum dan kuprum/ Set II: Iron and copper

Elektrod/ Electrodes Ferum/ Iron Kuprum/ Copper
Pengoksidaan atau penurunan Pengoksidaan/ Oxidation Penurunan/ Reduction
Oxidation or reduction
Setengah persamaan tindak balas Fe ➝ Fe + 2e – Cu + 2e ➝ Cu
2+
–
2+
Reaction half-equations
Persamaan ion keseluruhan Fe + Cu ➝ Fe + Cu
2+
2+
Overall ionic equation
2+
2+
Notasi sel/ Cell notation Fe(p/s) | Fe (ak/aq) || Cu (ak/aq) | Cu(p/s)
E 0 = E 0 – E 0
Nilai voltan sel (V) sel/cell katod/cathode anod/anode
Voltage value of the cell (V) = (+0.34 V) – (–0.44 V)
= 0.78 V
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