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Form
            4          Mathematics   Chapter 7 Graphs of Motion


                3.                                            Solve problems involving speed-time graphs
                Speed             Positive gradient represents
                                  acceleration (Speed keeps
                                  on increasing)                 Example 12
                O        Time                                 The diagram below shows the speed-time graph
                                              Zero            for the movement of two particles P and Q in a
                                              gradient
                Speed                                         period of 30 seconds.
                                  Interpretation   represents        Speed (m s )
                                                                            –1
                                  of speed-time   zero
                                    graph     acceleration         20                  B
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                O        Time                 (Uniform
                                              speed)               16  C
                Speed                                               u          D
                                  Negative gradient
                                  represents deceleration             A
                O        Time     (Speed keeps on decreasing)       O         18 F    30 E  Time (s)
                   Example 11                                 Graph AB represents the movement of particle P
                                                              whereas graph CDE represents the movement of
               The speed-time graph below shows Maria’s run in   particle Q.
               a sports practice.                             (a)  Determine the value of u.
                      Speed (m s )                            (b)  By using the value of u obtained in (a), find
                             –1
                     10    A         B                            the acceleration of particle  Q  in  the  first
        CHAP.                                                     18 seconds.
         7                                                    (c)  Calculate the difference between the distance
                                                                  travelled by particles P and Q in the period of
                                                                  30 seconds.
                                        C
                      O                    Time (s)
                           5        15  18                     Solution:
               (a)  Find the acceleration, in m s , for the   (a)  Gradient AD  = gradient AB
                                         –2
                   (i)  first 5 s,                                        u   =  20
                   (ii)  duration of time from 5 s until 15 s,            18  30
                   (iii)  last 3 s.                                        u =  20  × 18
               (b)  Hence, describe Maria’s run in the period of              30
                   18 s.                                                    = 12
                                                              (b)  Acceleration  = gradient CD
                Solution:                                                   = –  16 – 12
               (a)  (i)  Acceleration  = gradient OA                            4  18
                                 =  10                                      = –  18
                                   5
                                                                               2
                                 = 2 m s –2                                 = –   m s –2
                   (ii)  Acceleration = gradient AB                            9
                                 = 0 m s –2                   (c)  Distance travelled by particle P
                   (iii)  Acceleration = gradient BC              = area of triangle ABE
                                                                    1
                                 = –   10                         =  2  × 30 × 20
                                    18 – 15                       = 300 m
                                    10
                                 = –   m s –2                     Distance travelled by particle Q
                                    3
                   BRILLIANT Tips                                 = area of trapezium ACDF + area of triangle
                                                                   DEF
                                                                                     1
                 Negative acceleration is known as deceleration.  =  1  × (16 + 12) × 18 +   × 12 × 12
                                                                    2                2
                                                                  = 252 + 72
               (b)  For the first 5 s, Maria ran from 0 m s  until
                                                  –1
                   10 m s  with acceleration 2 m s . After        = 324 m
                         –1
                                                –2
                   that, she ran with speed 10 m s  for 10 s      Difference between the distance travelled by
                                              –1
                                                                  particles P and Q = 324 – 300
                   and decreased her speed with deceleration                    = 24 m
                    1
                   3   m s  until finally stopped.
                         –2
                    3                                           Try question 6 in Formative Zone 7.2
                 Try question 5 in Formative Zone 7.2
               144                                                                           7.2.3  7.2.4

         ENG07 Spotlight Matematik F4.indd   144                                                       16/03/2021   8:58 AM
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