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MODUL • Fizik TINGKATAN 5



                   Latihan / Exercise
                 1  Tentukan rintangan berkesan merentasi PQ bagi setiap litar berikut:
                     Determine the effective resistance across PQ for each of the following circuits:
                     (a)       20 Ω    10 Ω    5 Ω              (c)                            8 Ω
                         P                            Q                     10 Ω    20 Ω
                                                                       P                  Y    8 Ω    Q
                                                                  KBAT
                     (b)         8 Ω                            (d)            8 Ω     8 Ω
                                 8 Ω                                               8 Ω
                                                                  KBAT
                         P       8 Ω       Q                           P       4 Ω     4 Ω      Q
                     Penyelesaian / Solution

                    (a)  R  = 20 Ω + 10 Ω + 5 Ω        (c)  1     1      1                (d)  1      1       1     1
                         PQ                                    =      +                           =        +     +
                            = 35 Ω                         R YQ  8 Ω    8 Ω                   R PQ   16 Ω    8 Ω   8 Ω
                                                            1     2                            1     1 + 2 + 2
                    (b)   1     1      1     1             R   =   8 Ω                        R   =    16 Ω
                             =      +      +                YQ                                 PQ
                         R PQ  8 Ω    8 Ω   8 Ω                                                1      5
                          1     3                         \ R  = 4 Ω                              =                            UNIT 2
                                                             YQ
                             =                                                                R PQ   16 Ω
                         R PQ  8 Ω                        \ R  = 10 Ω + 20 Ω + R                     16 Ω
 UNIT 2
                               8 Ω                           PQ                YQ            \ R  =
                       \ R  =                                  = 10 Ω + 20 Ω + 4 Ω              PQ    5
                           PQ   3                              = 34 Ω                             = 3.2 Ω
                             = 2.67 Ω
                 2  Tentukan bacaan ammeter bagi litar berikut apabila suis dihidupkan.
                     Determine the ammeter reading for following circuit when the switch is turned on.
                     (a)              8 Ω             (b)                             (c)
                KBAT                                           4.5 V                          24 V
                         X  8 Ω  Y           Z                           S                                S
                                      8 Ω
                                                                        2 Ω                               6 Ω
                        A                                  8 Ω     A     R2                  8 Ω   I2  A           2.5 Ω
                                                           R1           2 Ω                               2 Ω
                                S                       X      Y         R3   Z          U       X               Y      Z
                     Penyelesaian     20 V                                                            I3
                     Solution
                                                                                                 I        2 Ω
                    (a)   V   = IR XZ                 (b)  V   = I R XZ                           2  A
                                                                 XZ
                                                             XZ
                           XZ
                          1   =   1   +   1                1   =   1   +   1              I                R 2
                         R YZ  8 Ω    8 Ω                  R YZ  2 Ω    2 Ω                  Y            2 Ω        Z
                          1     2                          1      2
                             =                                 =                                 I
                         R YZ  8 Ω                         R YZ  2 Ω                              3        R 3
                        \ R  = 4 Ω                       \ R  = 1 Ω
                           YZ                                YZ                        Dari bahagian litar yang merentasi YZ,
                       \ R  = R  + R                     \ R  = R  + R                 From the section of the circuit across YZ,
                           XZ   XY   YZ                      XZ   XY   YZ
                             = 8 Ω + 4 Ω                       = 8 Ω + 1 Ω                I  = I XZ
                             = 12 Ω                            = 9 Ω                        = 0.5 A


                         \ I =   V                        \ I =   V XZ                 Tetapi / But
                                R XZ                         XZ  R
                               20 V                                XZ                     I   = I 3
                                                                                          2
                             =   12 Ω                          =   4.5 V               (Kerana R  = R )
                                                                  9 Ω
                                                                                                   3
                                                                                               2
                             = 1.67 A                          = 0.5 A                \ 2 I = I
                                                                                          2
                                                                                        2 I = 0.5 A
                                                                                          2
                                                                                          I = 0.25 A
                                                                                          2
                                                                                        \ Bacaan ammeter
                                                                                          Ammeter reading   = 0.25 A
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