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MODUL • Fizik TINGKATAN 5

(c) V = I R UZ \ I = V UZ Dari bahagian litar yang merentasi XY,
UZ
UZ
1 = 1 + 1 UZ R UZ From the section of the circuit across XY,
R XY 6 Ω 2 Ω 24 V I = V XY
1 4 = 12 Ω 2 6 Ω
=
R XY 6 Ω = 2.0 A = 3.0 V
\ R = 6 Ω Dari litar, / From the circuit, 6 Ω
XY 4 = 0.5 A
\ R = 1.5 Ω V = I R
XY XY XY XY
\ R = R + R + R = I UZ (1.5 Ω) \ Bacaan ammeter = 0.5 A
UZ UX XY YZ (Kerana I = I ) Ammeter reading
= 8 Ω + 1.5 Ω + 2.5 Ω XY UZ
= 12 Ω = 2.0 A × 1.5 Ω
= 3.0 V

3 Tentukan bacaan voltmeter bagi litar berikut apabila suis dihidupkan.
Determine the ammeter reading for the following circuit when the switch is turned on.
(a) (b) 6 V
24 V
KBAT S S UNIT 2

12 Ω
UNIT 2
X 8 Ω Y 4 Ω K L 9 Ω
Z 4 Ω M
V V
Penyelesaian
Solution
(a) Pertama, kirakan nilai bagi I (b) Kira nilai bagi I KM terlebih dahulu.
Firstly, calculate value of I Calculate the value of I first.
KM
V = I R XZ 1 = 1 + 1
XZ
XZ
\ 24 V = (I ) × (12 Ω) R 12 Ω 4 Ω
XZ KL
I = 24 V 1 = 4
XZ
12 Ω
= 2 A R KL 12 Ω
Arus yang melalui setiap \ R = 12 Ω
perintang adalah sama. KL 4
Oleh itu, beza keupayaan bagi = 3 Ω
8 Ω ialah
The current passing through each \ R KM = 3 Ω + 9 Ω
of the resistors is the same. So
the potential difference of the 8 Ω = 12 Ω
resistor is V KM = I KM R KM \ V = I R
V = I R XY V KL KL KL
XY
XY
= 2 A × 8 Ω \ I KM = R KM Tetapi / But
= 16 V KM I KL = I KM
6 V
= = 0.5 A
12 Ω \ V = 0.5 A × 3 Ω
Video = 0.5 A KL
= 1.5 V

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Series and Parallel Circuit
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