Page 744 - Elementary_Linear_Algebra_with_Applications_Anton__9_edition
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Thus, the number of operations required to complete successive steps is as follows:
   Steps 1 and 1a.

   Steps 2 and 2a.

   Steps 3 and 3a.

Steps and a.

Step n.

Therefore, the total number of operations required to reduce  to row-echelon form is

or, on applying Formulas 1 and 2,

                                                                                                                      (5)

                                                                                                                      (6)

This completes the operation count for the forward phase. For the backward phase we must put the row-echelon form of
into reduced row-echelon form by introducing zeros above the leading 1's. The operations are as follows:
   739   740   741   742   743   744   745   746   747   748   749