Page 111 - Lecture Notes DCC3113

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1. Heavy trucks and buses are responsible for a majority of flexible pavement damage. Figure
shows two axles vehicle is loaded with 200 kN. Calculate the load equivalency factor for the
vehicle.

100 kN 100 kN
Figure :
(4 marks)
e (2 axle) = (L 1 / 80) + (L 1 / 80)
4
4
_____________________________________________________________________________________
4
4
= (100 / 80) + (100 / 80)
_____________________________________________________________________________________
=
4.9
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2. From the data below, determine:
i. Initial annual commercial traffic for one way, Vo .
ii. Cumulative commercial traffic for the design period, Vc .
(The required follow as a JKR Malaysia Design Method on these data)
Descriptions Data
Carriageway width 7.5 m
Shoulder width 2.0 m
ADT, both ways 9,600
Percentage of commercial vehicles 15%
Traffic growth rate 7%
Subgrade CBR 5%
Terrain Rolling
(6 Marks)

i. Initial annual commercial traffic for one way , Vo .
Vo = PLH x ½ x 365 x Pc

= 9600 x ½ x 365 x 0.15 = 262800
ii. Cumulative commercial traffic for the design period, Vc .

x
Vc = Vo [(1 + r) - 1]/ r
10
= 262800 [(1 + 0.07) - 1]/0.07 = 3630962.524 x 10 6

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