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Document Title
                Fundamentals of Stress and Vibration                                  Chapter Title
                [A Practical guide for aspiring Designers / Analysts]              2. Engineering Mechanics


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                 ƒ–Їƒ–‹…ƒŽŽ›ǡ ™‡ Šƒ˜‡ǣ

















                                         [Fig 2.57: flange dimensions for torque computation]

                                  total force on the flange area                 F total
                 Pressure force =                            ∗ elemental area  =       ∗  2πr ∗ dr
                                     total area of the flange                     πR 2

                The friction torque due to elemental area is given by:


                                                                 F total
                 Friction torque =  pressure force ∗ radius ∗ μ  =     ∗  2πr ∗ dr   ∗ r ∗ μ
                                                                 πR 2

                                     2F total
                                               2
                =  Friction torque =       ∗  r ∗ dr  ∗ μ
                                       R 2
                The total friction torque the joint could support is got by integrating the friction torque due to
                elemental are across the radius (R) of the flange.


                                       R                                 R
                                         2F total                2F total  μ
                                                   2
                                                                            2
                 Friction torque total  =      ∗  r ∗ dr  ∗ μ  =          r ∗ dr
                                           R 2                     R 2
                                      0                                 0
                                         2F total  μ r 3  R  2F total  μR
                =  Friction torque    =               =
                                 total
                                           R 2    3           3
                                                    0
                Equating the total friction torque with the total torque (100 Nm) to be supported, we get:

                                                                  2F     μR
                 Friction torque total  = Torque to be transmitted  =     total    = 100
                                                                      3

                                            300         300
                Therefore, we have:  F total  =      =            = 2500N
                                            2μR     2 ∗ 0.3 ∗ 0.2
                                                                                     2500
                Since there are 12 bolts, each bolt should carry a clamping or preload of     = 208.33N
                                                                                      12
                   Page 66      QP No. SSC/Q4401, Version 1.0, NSQF Level 7, Compliant with Aero and Auto Industries,
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