Page 11 - PRE-U STPM CHEMISTRY TERM 1
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Chemistry Term 1  STPM
                   9  The first line in the Lyman series corresponds to n  = 1 and n  = 2,
                                                                          2
                                                                1
                    while the second line corresponds to n  = 1 and n  = 3 and so on.
                                                      1        2
                  10  The same applies to the other series.

                     Example 2.1                                                                                CHAPTER


                  Calculate the wavelengths and frequencies of the following lines in                          2
                  the emission spectrum of hydrogen.
                  (a)  First line in the Balmer series.
                  (b)  Last line in the Balmer series.


                  Solution
                  (a)  Using n  = 2 and n  = 3
                             1
                                       2
                          1  = 1.097  10    1  –  
                                                1
                                        7
                          λ                2 2  3 2
                          1   = 1.534  10 m –1
                                        6
                          λ
                                      –7
                      ∴ λ  = 6.52  10  m  or
                            = 652 nm
                             C     3.0 × 10 8
                          f =    =           = 4.60 × 10  Hz
                                                      14
                             λ    6.52 × 10 –7
                  (b)  Using n  = 2 and n  = ∞
                                       1
                             1
                          1   = 1.097 × 10    1   –   1  
                                        7
                          λ               2 2  ∞ 2
                          1   = 2.74 × 10  m –1
                                       6
                          λ
                         ∴λ  = 3.65  10  m  or
                                        –7
                             = 365 nm
                              C     3.0 × 10 8
                           f  =     =       –7  = 8.22  10  Hz
                                                        14
                               λ   3.65 × 10
                 Bohr's Model of the Hydrogen Atom                                          2009/P1/Q3

                  1  In order to explain the formation of the line spectrum of hydrogen,   2014/P1/Q18(a)
                    Niels  Bohr, a Danish physicist, put forward his model of the
                    hydrogen atom in 1913. [He received the Nobel Prize for physics         Bohr's Model of the
                    in 1922 for his theory explaining the emission line spectrum of         Hydrogen Atom
                    hydrogen].                                                      VIDEO
                  2  He postulated that electrons revolve round the nucleus in fixed     Concept of orbit:
                    circular paths of different radii called orbits, much like the planets   A fixed circular path
                    revolving around the Sun.
                  3  The energy of the orbits is quantised. Each orbit is represented by
                    an integer, n, which is called the principle quantum number.





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         02 Chapter 2.indd   41                                                                         3/26/18   3:14 PM
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