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Mathematics Term 1  STPM  Chapter 2 Sequences and Series

                   Example 5

                Express each of the following series by using the summation notation ∑.
                (a)  1 + 4 + 9 + 16 +  …  + 100
                (b)  1 · 2 + 2 · 3 + 3 · 4 +  …  + 19 · 20

                                                                           2
                                                                      2
                                                                  2
                                                                                        2
                                                                               2
                Solution:           (a)  1 + 4 + 9 + 16 +   …  + 100 = 1  + 2  + 3  + 4  +  …  + 10
                                               th
                                         ∴ the r term, u  = r 2        10
                                                      r
                                         Hence, the series may be written as  ∑ r .
                                                                          2
                                                                       r = 1
                                    (b)  The r  term, u  = r(r + 1).   19
                                             th
                                                     r
                                         Hence, the series may be written as  ∑ r(r + 1).                   2
                                                                       r = 1
                   Example 6
                Rewrite each of the following series by using the summation notation ∑.
                (a)  2 + 5 + 10 + 17 +  …  + 401                     (b)   1  +   1  +   1  +  …  +   1
                                                                          2   3    4       50
                Solution:           (a)  2 + 5 + 10 + 17 +  …  + 401
                                                                       2
                                            2
                                                                                     2
                                                              2
                                         = (1  + 1) + (2  + 1) + (3  + 1) + (4  + 1) +  …  + (20  + 1)
                                                     2
                                             th
                                                        2
                                         The r  term, u  = r  + 1, (1  r  20)
                                                     r
                                                                       20
                                         Hence, the series may be written as  ∑ (r  + 1).
                                                                           2
                                                                       r = 1
                                    (b)   1  +   1  +   1  +  …  +   1
                                         2   3    4       50
                                         =   1   +   1   +   1   +  …  +   1
                                           1 + 1  2 + 1  3 + 1       49 + 1
                                                          1
                                             th
                                         The r  term, u  =  r + 1  , 1  r  49.
                                                     r
                                                                       49
                                         Hence, the series may be written as  ∑    1   .
                                                                       r = 1 r + 1
                   Example 7
                Write down the first three terms and the last term of the following series.
                     20                                                   10
                (a)   ∑ r(r + 2)                                     (b)  ∑ (–1) r + 1 r
                                                                                   2
                     r = 1                                                r = 1
                Solution:           (a)  The r  term,  u  = r(r + 2)
                                             th
                                                      r
                                         Thus        u  = 1(1 + 2) = 3
                                                      1
                                                     u  = 2(2 + 2) = 8
                                                      2
                                                     u  = 3(3 + 2) = 15
                                                      3
                                         The last term,  u  = 20 (20 + 2) = 440
                                                      20
                                    (b)  The r  term,  u  = (–1) r + 1 r
                                                                2
                                             th
                                                      r
                                                             2 1
                                         Thus        u  = (–1)  2  = 2
                                                      1
                                                     u  = (–1)  2  = –4
                                                             3 2

                                                      2
                                                     u  = (–1)  2  = 8
                                                             4 3
                                                      3
                                         The last term,  u  = (–1)  2  = –1024
                                                             11 10
                                                      10
                                                                                                      97
       02 STPM Math T T1.indd   97                                                                     3/28/18   4:21 PM
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