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Matematik   Tingkatan 2  Bab 2
            14.  Permudahkan setiap yang berikut.    SP 2.3.2     TP3
               Simplify each of the following.

                Pendaraban ungkapan algebra                       Pembahagian ungkapan algebra
                Multiplication of algebraic expressions           Division of algebraic expressions
                 2m – 2n  ×  4x + 4y    Faktorkan sebutan sepunya.  4b   ÷  a + 1
                  x + y      10           Factorise common term.  2b + 1   5b           Tukar ÷ kepada × dan salingan
                                                                                                5b
                    1             1                                   4b     5b         a + 1  ialah  a + 1 .
                                                                                         5b
                =   2(m – n)  ×  4(x + y)    Pemudahkan           =  2b + 1   ×  a + 1  Convert ÷ to × and the reciprocal of
                    x + y  1   10  5        Simplify                       2            a + 1  is   a + 1  .
                                                                                              5b
                                                                                         5b
                                                                        20b
                =   4(m – n)                                      =  (2b + 1)(a + 1)
                      5
                      3m      m  + m – 6                             4a – 4b   a – b
                                2
                (a)          ×                                   (e)         ÷
                     m  – 9      6m 2                                  9b      18a
                       2
                              1               1                           1       2
                    =      3m       ×  (m – 2)(m + 3)                =  4(a – b)   ×   18a
                      (m – 3)(m + 3)     6m 2                            9b      a – b
                                1           2m                           1        1
                       (m – 2)                                         8a
                    =                                                =
                      2m(m – 3)                                         b




                      p  + p    q + 2                                 3q – 1    q – 5
                       2
                (b)           ×                                  (f)         ÷
                    2pq + 4p   3p + 3                                3q – 21   4q – 28
                      1 p(p + 1)  1  q + 2  1                                        1
                    =          ×                                        3q – 1   4(q – 7)
                      2p(q + 2)  3(p + 1)                            =  3(q – 7)   ×   q – 5
                        1     1         1                                    1
                      1
                    =                                                =  4(3q – 1)
                      6                                                3(q – 5)





                                                                                  2
                      1                                              3x + 3y     x  – y 2
                (c)        × xy + x y                            (g)         ÷
                                 2
                    1 – x 2                                           4z + 2   4z  + 4z + 1
                                                                                 2
                           1                1                              1         1
                    =              × xy(1 + x)                          3(x + y)  (2z + 1)(2z + 1)
                      (1 – x)(1 + x) 1                               =  2(2z + 1)  ×   (x + y)(x – y)
                                                                           1
                    =  xy                                              3(2z + 1)      1
                      1 – x                                          =
                                                                        2(x – y)



                                2
                    my – ny    x  – y 2                               (y + 3) 2  3y + 9
                (d)         ×                                    (h)          ÷
                      x + y   m  – mn                                 16 – x 2  8 – 2x
                                2
                                       1
                      y(m – n)  1  (x + y)(x – y)                      (y + 3) 2  8 – 2x
                    =          ×                                     =   4  – x 2   ×   3y + 9
                                                                         2
                        x + y 1    m(m – n)  1
                       y(x – y)                                         (y + 3)(y + 3) 1  2(4 – x)  1
                    =                                                =               ×
                         m                                              (4 + x)(4 – x)  1  3(y + 3)  1
                                                                        2(y + 3)
                                                                     =
                                                                        3(4 + x)




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      02 Power Up Mate Tg2.indd   22                                                                           05/10/2020   5:01 PM
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