Page 7 - Focus SPM KSSM F4 2020 - Chemistry
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Chemistry Form 4  Chapter 3 The Mole Concept, Chemical Formula and Equation
          5.  We can solve various problems by comparing     3.  One  molecule  is  made  up  of  a  few  atoms.
            the  relative  atomic  masses  of  elements.  See   Therefore,  we  can  calculate  the  relative
            Examples 3.1 and 3.2.                          molecular  mass  of  a  substance  by  adding
                                                           up the relative atomic masses of all the
                                                           atoms that form the molecule.  To  do
        EXAMPLE  3.1
                                                           so, you need to know the formula of the
         How many beryllium atoms have the same mass       substance.  See  Figure  3.2  and  Table  3.1.
         as two silver atoms?                                                      Carbon diokside
         [Relative atomic mass: Be, 9; Ag, 108]                          O  C  O   molecule, CO 2
         Solution                                            RAM for O = 16       RAM for O = 16
         The number of beryllium atoms = n                              RAM for C = 12
         The  mass  of  n  beryllium  atoms  =  Mass  of  2         RMM for CO 2  = 16 + 12 + 16 = 44
         silver atoms                                       Figure 3.2  Calculating the relative molecular mass of
         So, n × RAM of Be = 2 RAM of Ag                           carbon dioxide
                       n × 9 = 2 × 108                    Table 3.1 Calculation of relative molecular mass of   Chapter
                         n =   2 × 108                    Molecular    several substances
                                 9
                                                                    Formula of
                                                                              Relative molecular mass,
                           = 24 atoms                    substance  substance         RMM             3
                                                        Hydrogen       H      2(1) = 2
                                                        gas             2
        EXAMPLE  3.2                                    Oxygen gas     O 2    2(16) = 32
                                                        Water         H O     2(1) + 16 = 18
                                                                       2
         How  many  times  is  the  mass  of  a  zinc  atom   Ammonia   NH    14 + 3(1) = 17
         larger than the mass of a helium atom?                         3
         [Relative atomic mass: He, 4; Zn, 65]          Ethanol     C H OH    2(12) + 5(1) + 16 + 1 = 46
                                                                       5
                                                                      2
         Solution                                      [Relative atomic mass: H, 1; C, 12; N, 14; O, 16]
           Mass of a zinc atom    RAM of Zn            Relative Formula Mass, RFM
          Mass of a helium atom  =   RAM of He           1.  The  term  ‘relative  molecular  mass’  is  only
                                 65                        used for substances made up of molecules. For
                               =
                                 4                         substances made up of ions, we use the term
                               = 16.25 times               ‘relative formula mass’.
                                                         2.  In  the  same  manner,  we  can  calculate  the
                                                           relative formula mass of an ionic substance by
        Relative Molecular Mass, RMM                       adding up the relative atomic mass of all the
          1.  Based on carbon-12 scale, relative molecular   atoms of elements shown in the formula. See
            mass of a substance is defined as the average   Table 3.2.
            mass of a molecule of the substance compared   Table 3.2  Calculation of relative formula mass of a few
                                                                  substances
            to      1    of the mass of a carbon-12 atom.
               12                                       Ionic substance  Formula of   Relative formula mass,
                                                                      substance        RFM
                             Average mass of one        Sodium chloride  NaCl   23 + 35.5 = 58.5
         Relative molecular   =   molecule of the substance  Aluminium oxide    Al O 3  2(27) + 3(16) = 102
                                                                         2
         mass of a substance       1     mass of one    Calcium       Ca (OH)  40 + 2[16+ 1]= 74
                                  ×
                               12
                                          carbon-12 atom  hydroxide         2
                                                        Magnesium     Mg (NO )  24 + 2[14 + 3(16)] = 148
                                                        nitrate            3 2
          2.  For example, the relative molecular mass of   Copper(II)         64 + 32 + 4(16) + 5[2(1) +
            carbon  dioxide  is  44.  This  means  that  one   sulphate hydrate  CuSO .5H O  16] = 250
                                                                         4
                                                                            2
            molecule of carbon dioxide is 44 times   1   the   [Relative atomic mass : H,1; N, 14; O, 16; Na, 23,
            mass of a carbon-12 atom.        12        Mg, 24; S, 32; Cl, 35.5; Ca, 40; Cu, 64]

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 03 SPM CHEMISTRY F4.indd   35                                                               27/02/2020   11:23 AM






                                  Jisim molekul relatif bahan  =    Jisim purata satu molekul bahan
                                                                     /  x jisim satu atom karbon-12
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