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Chemistry Form 4  Chapter 3 The Mole Concept, Chemical Formula and Equation
          •   Room conditions refer to the temperature
              of 25ºC and the pressure of 1 atm.     EXAMPLE 3.11
                                                       What is the volume of 1.2 moles of neon gas at
                                                       STP?
               1 mole of H 2  1 mole of O 2  1 mole of N 2  [Molar volume: 22.4 dm  mol  at STP]
                                                                           3
                                                                                -1
                                                       Solution
                                                       The volume of neon gas
      Figure 3.6  Each balloon has 6.02 x 10  molecules and has   = number of moles × molar volume
                                 23
              the volume of 22.4 dm  at STP            = 1.2 × 22.4 dm 3
                              3
                                                       = 26.88 dm 3
       4.  Number of moles and volume of gas are linked
          by molar volume as shown below.
            Number     × molar volume   Volume       EXAMPLE 3.12
           of moles    ÷ molar volume    of gas        100 cm  of carbon dioxide gas is collected in a
                                                             3
                                                       reaction at room conditions. How many moles
  Chapter
 3                    SPM Tips                         of carbon dioxide is produced? [Molar volume:
                                                       24 dm  mol  at room conditions]
                                                            3
                                                                -1
       In calculations, make sure that the volume of gas and
       molar volume are of the same unit, which means that   Solution
                               3
       both are in cm  or both are in dm . The changing of   The volume of carbon dioxide gas = 100 cm 3
                 3
       unit is as follows .                               100
                    1 dm  = 1000 cm 3                  =   1000  dm  = 0.1 dm 3
                        3
                                                                 3
                                                       The number of moles of carbon dioxide
                                                       produced
                                                       = Volume of gas ÷ molar volume
                                                          0.1
                                                       =   24   = 0.0042 mol



     Number moles, number of particles, mass and volume
       1.  The following shows the relationships between all quantities of chemicals.
                                     ÷ N                        × Molar mass
                                                           of
                                                  Number
                  Number of             A        Bilangan mol                    Mass
                   particles          × N A         moles        ÷  Molar mass
                                        × Molar volume  ÷ Molar volume              Number
                                                                                    of moles
                                                 Volume of gas                      calculation
                                                                             VIDEO

       2.  Number of moles is the intermediate unit to convert other quantities of chemicals such as number of
          particles, mass and volume. See the examples below.

                                Table 3.4  Examples of conversion of quantity of chemicals
                     Conversion                               Calculation steps
           From number of particles to mass  Number of particles → number of moles → mass (see Example 3.13)
           From mass to volume of gas     Mass → number of moles → volume of gas (see Example 3.14)
           From volume of gas to number of particles  Volume of gas → number of moles → number of particles (see Example 3.15)


        40





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