Page 21 - Hybrid PBD 2022 Form 4 Additional Mathematics
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Matematik Tambahan Tingkatan 4 Bab 1 Fungsi
5. Selesaikan setiap yang berikut. SP 1.1.3 TP3
Solve each of the following.
(a) Fungsi h ditakrifkan oleh h : x → x + 3x + 2. Cari
2
Fungsi f ditakrifkan oleh f : x → 2x + 6 . Cari Function h is defined by h : x → x + 3x + 2. Find
2
1
2x + 6 3 (i) h(–3) dan / and h ,
Function f is defined by f : x → 3 . Find 2
3
(i) f(3) dan / and f , (ii) nilai-nilai x yang mungkin jika imejnya ialah
2
30.
(ii) nilai x jika imejnya ialah 10. the possible values of x if the image is 30.
the value of x if the image is 10.
2
3
2 + 6 (i) h(–3) = (–3) + 3(–3) + 2
= 2
3
(i) f(3) = 2(3) + 6 f = 2 2
1
1
1
3 2 3 h + 3 + 2
=
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= 4 = 3 2 2 2
(ii) f(x) = 10 = 15
2x + 6 = 10 4
3 (ii) x + 3x + 2 = 30
2
2x + 6 = 30 x + 3x – 28 = 0
2
2x = 24 (x – 4)(x + 7) = 0
x = 12 x = 4, –7
(b) Fungsi p ditakrifkan oleh p : x → kx + c. Diberi bahawa h(2) = 7 dan h(4) = –1, cari
Function p is defined by p : x → kx + c. Given that h(2) = 7 and h(4) = –1, find
(i) nilai k dan nilai c, (ii) imej bagi 3 di bawah p.
the value of k and of c, the image of 3 under p.
h(2) = 7 p(x) = –4x + 15
2k + c = 7......................a p(3) = –4(3) + 15
h(4) = –1 = 3
4k + c = –1....................b
a – b –2k = 8
k = –4
2(–4) + c = 7
c = 15
6. Selesaikan setiap yang berikut. SP 1.1.3 TP3
Solve each of the following.
Fungsi f ditakrifkan oleh f : x → |x − 1|.
Function f is defined by f : x → |x − 1|.
(i) Lakarkan graf bagi f untuk domain −2 x 3. (iii) Cari domain bagi f(x) 2.
Sketch the graph of f in the domain −2 x 3. Find the domain of f(x) 2.
(ii) Cari nilai bagi f(–5). (iv) Cari domain bagi f(x) 4.
Find the value of f(–5). Find the domain of f(x) 4.
(i) x –2 0 1 3 (ii) f(–5) = |–5 – 1|
= |–6|
y = f(x) = |x – 1| 3 1 0 2
= 6
f(x)
(iii) f(x) 2
3 x – 1 –2 , x – 1 2
x –1 x 3
2
(iv) f(x) 4
1 |x – 1| 4
–4 x – 1 4
x
0
–2 1 3 –3 x 5
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01 Hybrid PBD Mate Tambahan Tg4.indd 3 29/09/2021 3:23 PM
