Page 17 - Praktis Strategi 2020 Matematik - Tingkatan 2
P. 17

Matematik  Tingkatan 2  Bab 2 Pemfaktoran dan Pecahan Algebra

                   (c)  Permudahkan:                                    (b)  Sebuah segi empat sama digunting  daripada
                      Simplify:                                            sekeping kertas berukuran 21 cm lebar dan
                                                                           29.7 cm panjang. Lebihan panjang kertas yang
                                     2
                                    y  – 4  3y + 6
                                          ÷                                digunting  ialah  r. Hitung luas segi empat  sama
                                     4st     12s
                                                                           yang digunting.                [3 markah]
                                              [4 markah / 4 marks]          A square was cut off from a paper with measurement
                                                                           of  21 cm width  and 29.7 cm length.  The remaining
                                                                           length of the paper is r. Calculate the area of the cut
                       Tukarkan operasi bahagi  kepada operasi darab.      off square.                      [3 marks]
                       Kemudian,  lakukan pemfaktoran dan permudahkan
                       sebutan dan ungkapan yang serupa.                   Jawapan / Answer:
                       Change the division operation to multiplication operation.
                       Then, factorise and simplify the like terms and expression.          Panjang = Lebar = 29.7 – r

                                                                           Luas = (29.7 – r)(29.7 – r)
                      Jawapan / Answer:                                                                2
                                                                                 = 882.09 – 29.7r – 29.7r + r
                        2
                       y  – 4  3y + 6                                            = (r  – 59.4r + 882.09) cm 2
                                                                                   2
                              ÷
                        4st      12s
                         y  – 4   12s
                         2
                      =        ×
                          4st    3y + 6                                 (c)  Permudahkan:
                         y  – 2 2   12s                                    Simplify:
                          2
                      =         ×
                          4st     3(y + 2)                                 (b – 2)  – (9b  + 12b – 5) ÷ (3b – 1)
                                                                                      2
                                                                                 2
                                          3 1
                        (y + 2)(y – 2)  12s                                                        [4 markah / 4 marks]
                      =              ×
                             4st       3(y + 2)
                            1          1                                   Jawapan / Answer:
                         y – 2                                                   2    2
                      =                                                    (b – 2)  – (9b  + 12b – 5) ÷ (3b – 1)
                          t                                                             2
                                                                           = (b – 2)  –  (9b  + 12b – 5)
                                                                                   2
                                                                                        (3b – 1)
               2.  (a)  Kembangkan
                      Expand                                               = (b – 2)  –   (3b – 1)(3b + 5)
                                                                                   2
                      (i)  6h(1 − h)                                                     (3b – 1)
                      (ii)  2p(q − 3)                                         2
                                                                           = b  – 4b + 4 – (3b + 5)
                      (iii)  2p(q − 3)
                                              [3 markah / 3 marks]
                                                                              2
                                                                           = b  – 7b – 1
                      Jawapan / Answer:
                      (i)  6h(1 – h)
                          = 6h – 6h 2
                      (ii)  2p(q – 3)
                          = 2pq – 6p
                      (iii)  –5(4 – 9m)
                          = –20 + 45m














                                                               25                               © Penerbitan Pelangi Sdn. Bhd.







      02 Bab 2.indd   25                                                                                       11/12/19   12:28 PM
   12   13   14   15   16   17   18