Page 16 - Praktis Strategi 2020 Matematik - Tingkatan 2

Matematik Tingkatan 2 Bab 2 Pemfaktoran dan Pecahan Algebra

Bahagian A / Section A (b) Padankan kembangan yang betul bagi ungkapan
algebra yang diberi. [2 markah]
1. 3xy – 3yz – wx + wz = Match the correct expansions for the algebraic
A (3x – 3y)(w – z) expressions given. [2 marks]
B (3x – 3z)(w – y)
C (3y + w)(x – z) Jawapan / Answer:
D (3y – w)(x – z)
2
b – 2b + 1
4x (b – 9)(b + 9)
2
2. Ungkapkan × (5x + xy) sebagai satu
(5x + y)y 4
2
pecahan tunggal dalam bentuk termudah. b – 18b + 81
4x (b – 1)(b – 1)
2
Express × (5x + xy) as a single fraction in its
(5x + y)y 4
2
simplest form. b – 81
4x
A
y 4
4xy Bahagian C / Section C
B 4
y 1. (a) (i) Kembangkan (y + 4)(y – 5). [2 markah]
4x 2 Expand (y + 4)(y – 5). [2 marks]
C 4
y (ii) Faktorkan 9x + 3. [1 markah]
4x Factorise 9x + 3. [1 mark]
D
xy 4 Jawapan / Answer:
(i) (y + 4)(y – 5)
2
3. Faktorkan 12p + 8p –15. = y – 5y + 4y – 20
2
2
Factorise 12p + 8p – 15.
2
= y – y – 20
A (4p + 3)(3p – 5)
B (4p – 3)(3p + 5) (ii) 9x + 3 = 3(3x + 1)
C (6p – 5)(2p + 3)
D (6p + 5)(2p – 3) (b) Selesaikan gabungan operasi berikut.
Solve the following combined operations.
Bahagian B / Section B p 4
2
+ (36q + 24p)
1. (a) Lengkapkan pemfaktoran ungkapan algebra yang q 6q
berikut menggunakan kaedah darab silang. [3 markah / 3 marks]
Complete the following expansion of algebraic
expressions using cross multiplication method. Jawapan / Answer:
2
2x – 11x – 6 p 4 2
q + 6q (36q + 24p)
[2 markah / 2 marks]
p + ( 144q 2 96p
= + )
Jawapan / Answer: q 6q 6q
p 16p
2x 1 x = + 24q +
q q
17p + 24q 2
=
x –6 –12x q
2x 2 –6 –11x

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