Page 29 - PBD Plus Matematik T5 (EG)
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Matematik Tingkatan 5  Bab 1 Ubahan
            9.  Ketumpatan suatu objek,  V, berubah secara        14.  Diberi  bahawa  A  berubah  secara  langsung
               langsung   dengan    jisim  objek,  m,   dan          dengan  B  dan  secara  songsang  dengan  C.  Jika
               secara songsang dengan isi padu objek,  I.            A = 6 apabila B = 4 dan C = 2, berapakah peratusan
               Diberi V = 25 apabila m = 10 dan I = 0.1. Ungkapkan   ubahan  bagi  A apabila  B bertambah  sebanyak
               V dalam sebutan m dan I.  sp 1.3.1                    20% dan C berkurang sebanyak 40%?
               Density of an object, V, varies directly as the mass of the object,   Given that A varies directly as B and inversely as C. If A = 6 when
               m, and inversely as the volume of the object, I. Given V = 25   B = 4 and C = 2, what is the percentage of the change of A when
               when m = 10 and I = 0.1. Express V in terms of m and I.  B increases by 20% and C decreases by 40%?
                      4m                     25m                                            sp 1.3.2  KBAT  Menganalisis
               A  V =                 C  V =
                       I                       I                     A  –50%               C  100%
                       m                     m                       B  50%                D  200%
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               B  V =                 D  V =
                       4I                     I
                                                                      TIP Menjawab
            10.  Berdasarkan jadual berikut, nyatakan hubungan        1  Cari pemalar bagi hubungan antara A, B dan C.
               antara W dan x.  sp 1.1.2                                 Find the constant of the relationship between A, B and C.
               Based on the table, state the relation between W and x.  2  Ungkapkan A dalam sebutan B dan C.
                                                                         Express A in terms of B and C.
                             W      40     48                         3  Hitung nilai  A apabila  B bertambah sebanyak 20%
                             x     100     144                           dan C berkurang sebanyak 40%.
                                                                         Calculate the value of A when B increases by 20% and C
                                                                         decreases by 40%.
               A  W = 4x              C  W = √x                       4  Tentukan peratusan ubahan bagi nilai A.
               B  W = 4x              D  W = 4√x                         Determine the percentage of the change of the value of A.
                         2
            11.  Bilangan liter cat,  x, yang diperlukan untuk
               mengecat satu dinding berubah secara langsung     KERTAS      2
               dengan luas dinding itu, y. Dicatatkan bahawa 5
               liter cat diperlukan untuk mengecat satu dinding     1.  Diberi bahawa  m berubah secara songsang
               yang  seluas  40  m .  Hitung  luas  dinding  yang    dengan punca kuasa dua  n dan  m = 3 apabila
                                2
               dicat, dalam m , jika 28 liter cat digunakan.         n = 36.  sp 1.2.2
                            2
               The number of litres of paint, x, used to paint a wall varies   Given that m varies inversely as the square root of n and m = 3
               directly as the area of the wall, y. It is recorded that 5 litres of   when n = 36.
               paint can cover a wall with an area of 40 m . Calculate the area   (a)  Ungkapkan m dalam sebutan n.
                                             2
                             2
               of wall painted, in m , if 28 litres of paint is used.  sp 1.1.4  Express m in terms of n.
               A  140                 C  350                                                    [2 markah / 2 marks]
               B  224                 D  714                         (b)  Hitung nilai n apabila m = 2.
            12.  Jadual di bawah menunjukkan nilai-nilai bagi            Calculate the value of n when m = 2.
               pemboleh ubah M dan N.   sp 1.2.3                                                [2 markah / 2 marks]
               The table shows the values of variables M dan N.      (c)  Hitung nilai m apabila n = 225.
                                                                         Calculate the value of m when n = 225.
                           M         a        c                                                 [2 markah / 2 marks]
                           N         b        5                      Jawapan / Answer :

               Diberi  bahawa  M  berubah  secara  songsang          (a)  m ∝   1
               dengan N dan nilai ab ialah 10. Hitung nilai c.                √n
               It is given that M varies inversely as N and the value of ab is 10.   k
               Calculate the value of c.                                 m =   √n
               A  2                   C  10                                    k
               B  5                   D  50                              3  =
                                                                             √36
            13.  Pecutan, a, sebuah lori berubah secara langsung         k  = 18
               dengan kuasa dua laju, v, dan secara songsang                  18
               dengan jarak,  s, yang dilalui oleh lori tersebut.        m =   √n
               Diberi bahawa a = 40 km j , v = 60 km j  dan                    18
                                        −2
                                                      −1
               s = 45 km. Hitung nilai s apabila a = 50 km j  dan    (b)    2  =   √n
                                                      −2
                         −1
               v = 80 km j .  sp 1.3.2                                   √n   = 9
               Acceleration, a, of a lorry varies directly as the square of speed, v,
               and inversely as the distance, s, travelled by the lorry. Given that    n  = 81
               a = 40 km h , v = 60 km h  and s = 45 km. Calculate the value   18
                       −2
                                  −1
               of s when a = 50 km h  and v = 80 km h .              (c)  m =
                                            −1
                               −2
               A  45 km               C  54 km                                √225
               B  46 km               D  64 km                             = 1.2
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