Page 26 - PBD Plus Matematik T5 (EG)

Matematik Tingkatan 5 Bab 1 Ubahan
26. Selesaikan. TP 4
Solve.
Contoh
Jadual di bawah menunjukkan perubahan tiga kuantiti, V, e dan m. Diberi V berubah secara songsang
dengan e dan punca kuasa tiga m. Hitung nilai x dan nilai y.
The table shows the changes of three quantities, V, e and m. Given that V varies inversely as e and the cube root of m. Calculate the
value of x and of y.
V 3.75 x 0.24
e 4 9 25
m 0.008 0.027 y
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1 3 3
V ∝ V = V =
3
3
3
e √m e √m e √m
k 3 3
V = 3 x = 0.24 =
e √m 9(√0.027) 25(√y )
3
3
k 10 3
3.75 = x = √y = 0.5
3
4(√0.008) 9 y = 0.125
k = 3
(a) Jadual di bawah menunjukkan perubahan tiga kuantiti, I, H dan P. Diberi I berubah secara songsang
dengan H dan kuasa dua P. Hitung nilai x dan nilai y.
The table shows the changes of three quantities, I, H and P. Given that I varies inversely as H and the square of P. Calculate the
value of x and of y.
I 12.5 x 0.025
H 14 35 y
P 0.2 0.4 2.0
1 7 7
I ∝ I = I =
HP 2 HP 2 HP 2
k 7 7
I = x = 0.025 =
HP 2 (35)(0.4) 2 y(2.0) 2
k x = 1.25 y = 70
12.5 =
(14)(0.2) 2
k = 7

(b) Jadual di bawah menunjukkan hubungan antara pemboleh ubah B, t dan S. Diberi bahawa B berubah
secara langsung dengan t dan secara songsang dengan kuasa dua S. Hitung nilai x dan nilai y.
The table shows the relation between variables B, t and S. Given that B varies directly as t and inversely as the square of S. Calculate
the value of x and of y.
11
B x 2
18
1
t 0.2 0.5
22
S 25 9 y

t 99t 1
B ∝ B = 99 1 2
S 2 S 2 22
kt 99(0.2) 2 = y 2
B = x =
S 2 25 2 2 9
11 = k(0.5) x = 0.03168 y = 4
18 9 2 y = ± 3
k = 99 2

Cuba jawab Praktis SPM 1, K2: S2

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