Page 27 - Hybrid PBD Matematik TG3_Edisi Guru

Matematik Tingkatan 3 Bab 1
7. Rajah di bawah menunjukkan pendaraban dua nombor dalam bentuk indeks dan hasil darabnya. Senaraikan
tiga set pendaraban nombor yang lain. SP 1.2.1 TP3 i-Think Peta bulatan
i-Think
i-Think
The diagram shows the multiplication of two numbers in index form and its product. List three other sets of multiplication of numbers.

6 × 6 13
2
Mana-mana jawapan lain
yang sesuai
6 × 6 12 6 15 Any other possible answers Tip Penting
3
Hukum indeks
6 × 6 10 Law of indices
5
6 × 6 11 • a × a = a m + n
4
m
n
• a × a × a = a m + n + p
p
n
m

8. Permudahkan setiap yang berikut. SP 1.2.1 TP3
Simplify each of the following.
(i) 6 × 6 = 6 1 + 5 (ii) 2m × 3m = (2 × 3) × (m × m )
2
5
5
5
2
= 6 Tip Penting Operasi untuk pekali
6
a = a 1 = 6m 2 + 5 Operation of the coefficients
= 6m 7
10
6
12
2
3
5
(a) (–0.2) × (–0.2) (b) p × p (c) 9 × 9 × 9
= (–0.2) 5 + 2 = p 6 + 12 = 9 1 + 3 + 10
= (–0.2) = p = 9
14
7
18
(d) 2x × x × 9x (e) y × 2y × 3y (f) – j × – 1 j × 24j
3
5
3
4
7
1 2
7
1 2
4
7
4
3
5
3
= (2 × 9) × (x × x × x ) = (2 × 3) × (y × y × y ) 4 3
1
3
4
1 2
= 18x 3 + 7 + 5 = 6y 3 + 1 + 4 = – × – 1 × 24 × (j × j × j )
2
4
7
= 18x 15 = 6y 8 4 3
= 2j 2 + 4 + 7
= 2j 13
9. Nyatakan dalam bentuk indeks paling ringkas. SP 1.2.1 TP3
State in simplest index form.
4 × 3 × 3 × 4 Kumpulkan asas yang sama.
5
3
2
4
= 4 × 4 × 3 × 3 Group the terms with the same base. Tip Penting
4
2
5
3
n
= 4 2 + 5 × 3 3 + 4 Tambahkan indeks bagi asas yang sama. –a ≠ (–a) n
Add the indices for terms with the same base.
= 4 × 3
7
7
3
2
5
3
(a) 3 × 5 × 3 × 5 (b) (–0.7) × 6 × (–0.7) × 6 (c) –u × 3v × 5v × u
4
2
4
6
3
2
4
6
= 3 × 3 × 5 × 5 = (–0.7) × (–0.7) × 6 × 6 = (–1 × 3 × 5) × (u × u × v × v )
4
2
3
3
3
4
6
2
2
4
6
5
= 3 6 + 4 × 5 2 + 3 = (–0.7) 4 + 5 × 6 2 + 6 = –15u 2 + 4 3 + 3
v
= 3 × 5 = (–0.7) × 6 = –15u v
5
8
10
9
6 6
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