Page 29 - Hybrid PBD Matematik TG3_Edisi Guru

Matematik Tingkatan 3 Bab 1
13. Lengkapkan setiap petak berikut. SP 1.2.2 TP3
Complete each of the following boxes.
(a) 5 7 ÷ 5 ÷ 5 = 5 (b) a 5 b ÷ a b 2 = ab 2
4
2
4
4
b
3
9
12 5
(c) a b × a 6 2 = a b 6 (d) 56a b × a b 2 = 7a 9 b
2
9
a b
9
8 a b
3
14. Selesaikan masalah berikut. SP 1.2.2 TP4
Solve the following problem.
8 × 3 y
x
5 × 2 y = 10, tentukan nilai x + y. 8 × 3 6 = 24, tentukan nilai x + y.
x
3
5 × 2 4 8 × 3 y
2
x
5 × 2 y = 10, determine the value of x + y. 8 × 3 6 = 24, determine the value of x + y.
x
3
5 × 2 4
2
8 × 3 y
x
5 × 2 y = 5 × 2 8 × 3 6 = 8 × 3
x
3
5 × 2 4 8 x – 3 = 8 3 y – 6 = 3 Maka/ Hence,
2
1
1
5 x – 2 = 5 2 y – 4 = 2 Maka/ Hence, x – 3 = 1 y – 6 = 1 x + y = 4 + 7
1
1
x – 2 = 1 y – 4 = 1 x + y = 3 + 5 x = 4 y = 7 = 11
x = 3 y = 5 = 8
15. Lengkapkan setiap petak berikut. SP 1.2.3 TP2
Complete each of the following boxes.
p
9
(a) 4 × 4 × 4 × 4 × 4 = (4 ) 5 (b) 2 × 2 × 2 × 2 × 2 × 2 × 2 = (2 ) 7 Secara generalisasi,
9
p
p
p
p
p
9
9
9
9
p
p
By generalisation,
4 9 + 9 + 9 + 9 + 9 = 4 45 2 p + p + p + p + p + p + p = 2 7p (a ) = a mn
m n
16. Permudahkan setiap yang berikut. SP 1.2.3 TP3
Simplify each of the following.
11 2
(a) (9 ) = 9 2 × 8 (b) (k ) = k 3 × 6 (c) (x ) = x 11 × 2
3 6
2 8
18
(3 ) = 3 4 × 3 = 9 = k = x
16
22
4 3
= 3
12
(d) (2y ) = 2 1 × 4 × y 3 × 4 (e) [(–5) ] = (–5) 2 × 3 (f) [(–j ) ] = (–j) 5 × 5
3 4
5 5
2 3
Tip Penting
= 16y = (–5) = (–j )
6
25
12
Hukum indeks
Law of indices
• (a ) = a mn
m n
17. Permudahkan setiap yang berikut. SP 1.2.3 TP3
Simplify each of the following.
(a) (9 × 8 × 4 ) (b) (2j kl )
3
2
6 2
5
6 5
(i) (3 × 4) = 3 4 × 3 × 4 1 × 3 = 9 5 × 2 × 8 3 × 2 × 4 = 2 × j 2 × 5 × k × l 6 × 5
5
6 × 2
3
4
5
= 3 × 4 = 9 × 8 × 4 12 = 2 j k l
5 10 5 30
12
10
3
6
2j
2 3
3
(ii) 1 2 = 2 × j 2 × 3 (c) (7m n) (d) 1 2 4 = 2 3 × 4
0
2
4
3
5k
3
3
5 × k
2 × 4
4
0 4
3 6
= 2 j = 7 m n 5 2 2 5 12
= 7 (1)n
4
4
5 k =
3 3
= 7 n 5 8
4 4
4 × p
x
4p
7
5
3 5
Tip Penting (e) 1 2 6 = x 7 × 6 (f) 1 2 = 3 × q 3 × 5
y
y
3q
2
5
2 × 5
1 × 6
mq nq a
m q
(a b ) = a b , 1 2 = a b mq = x 42 = 4 p
5 15
m n q
b
nq
n
y 6 3 q
5 10
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