Page 30 - Hybrid PBD Matematik TG3_Edisi Guru

Matematik Tingkatan 3 Bab 1
18. Lengkapkan setiap yang berikut. SP 1.2.4 TP2
Complete each of the following.
(a) (i) 2 × 2 × 2 × 2 = 1 (ii) p × p × p = 1 Secara generalisasi,
2 × 2 × 2 × 2 p × p × p By generalisation,
2 4 4 – 4 0 p 3 3 – 3 0 0
= 2 = 2 = p = p a = 1
2 4 p 3

(b) 2 × 2 × 2 × 2 1 p × p × p 1 Secara generalisasi,
(i) = (ii) = By generalisation,
2 × 2 × 2 × 2 × 2 × 2 × 2 2 3 p × p × p × p × p p 2
1
2 4 4 – 7 –3 p 3 3 – 5 –2 a = ; a ≠ 0
–n
= 2 = 2 = p = p a n
2 7 p 5

19. Tandakan ‘✓’ bagi pernyataan yang betul. SP 1.2.4 TP2
Mark ‘✓’ the correct statement.
0
0
0
0
0
(a) 1 = 0 (b) 2 = 1 ✓ (c) p = 1 ✓ (d) y = y (e) (–2) = –2
Tip Penting
1 1 a –n b n
=
• a = a n , a ≠ 0 • a –n = a , a ≠ 0 • 1 2 1 2 , b ≠ 0, a ≠ 0
–n
n
a
b

1
20. Lengkapkan yang berikut dengan menyatakan a sebagai n atau sebaliknya. SP 1.2.4 TP2
–n
1 a
Complete the following by stating a as or vice versa. i-Think Peta titi
–n
i-Think
i-Think
a n
ditulis dalam bentuk 1 n
is written in the form 1 a 4 –1 6 –2 9 –5 10 –6 p –7 (2x) –3 (jk) –6
a n as as as as as as
1 1 1 1 1 1 1
4 6 2 9 5 10 6 p 7 (2x) 3 (jk) 6

21. Ungkapkan setiap yang berikut dalam bentuk indeks positif. SP 1.2.5 TP3
Express each of the following in positive index form.
2
7
4
3
(a) 1 2 –1 = 5 (b) 6 1 –3 = 6 3 (c) x 1 –5 = x 5 (d) 1 2 –2 = 1 2 2 (e) 2 y = 9y 4
–4
9
4
5
3
7
22. Ungkapkan setiap yang berikut dalam bentuk indeks negatif. SP 1.2.5 TP3
Express each of the following in negative index form.
1
k
j
1
9
5
(a) 1 2 6 = 4 –6 (b) 3 = 3 1 –2 (c) 5 = 1 2 –1 (d) (–7) = (–7) –5 (e) 1 2 6 = 1 2 –6
2
4
k
5
9
j
23. Lengkapkan setiap yang berikut. SP 1.2.5 TP2
Complete each of the following.
2
3
2
3
(a) x = 25 x = 25 (b) x = 27 x = 27
1 1 1 1
3
3
3
√x = √5 (x ) 2 = (5 ) 2 √x = √3 (x ) 3 = (3 ) 3
3
3
2
2
3
2
2
x = 5 x = 5 x = 3 x = 3 1
1
1
1
1
n
Secara generalisasi, / By generalisation, √a = a n
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