Page 28 - Hybrid PBD Matematik TG3_Edisi Guru

Matematik Tingkatan 3 Bab 1
10. Lengkapkan setiap yang berikut. SP 1.2.2 TP2
Complete each of the following.

(a) 2 × 2 × 2 × 2 × 2 × 2 = 2 6 (b) p ÷ p = p 8 Secara generalisasi
By generalisation,
8
4
2 × 2 × 2 3
2 p 4 a ÷ a = a m – n
m
n
2 × 2 × 2 × 2 × 2 × 2 = 2 3 p × p × p × p × p × p × p × p = p 4
2 × 2 × 2 p × p × p × p
11. Rajah di bawah menunjukkan pembahagian dua nombor dalam bentuk indeks dan hasil bahaginya.
Senaraikan tiga set pembahagian nombor yang lain. SP 1.2.2 TP3 i-Think Peta bulatan
i-Think
i-Think
The diagram shows the division of two numbers in index form and its quotient. List three other sets of division of numbers.

7 ÷ 7 5
10
Mana-mana jawapan lain Tip Penting
yang sesuai
7 ÷ 7 3 7 5 Any other possible answers Hukum indeks
8
Law of indices
• a ÷ a = a m – n
m
n
7 ÷ 7
6
7 ÷ 7 4
9

12. Permudahkan setiap yang berikut. SP 1.2.2 TP3
Simplify each of the following.

7 9
6 2
(i) 4 ÷ 4 (ii) 54a b ÷ 9a b
5
11
= 4 11 – 5 = 54 a 7 – 6 9 – 2
b
= 4 9
6
= 6ab
7
(a) 8 ÷ 8 = 8 6 – 2 (b) 3 18 = 3 18 – 9 (c) x ÷ x ÷ x = x 16 – 4 – 2
4
2
6
2
16
10
4
= 8 3 9 = x
= 3
9

2
2
10
3
7
2
14y 7 (e) 36k ÷ 6k ÷ k (f) –25m ÷ 5m ÷ 5m
7
(d) 14y ÷ 2y =
2y = 36k 7 ÷ k 2 = –25m 10 ÷ 5m
3
= 7y 7 – 1 6k 2 5m 2
3
= 7y 6 = 6k 7 – 2 ÷ k 2 = –5m 10 – 2 ÷ 5m
3
5
8
= 6k ÷ k 2 = –5m ÷ 5m
= 6k 5 – 2 = –1m 8 – 3
= 6k = –m
5
3
7 6
4 8
2 4
y
(g) x y ÷ x y = x 9 – 3 11 – 9 (h) 35g h ÷ 5g h (i) 121m n = 11m 7 – 1 6 – 5
9 11
n
3 9
5
= x y = 35 g 4 – 2 8 – 4 11mn = 11m n
6 2
6
h
5
=7g h
2 4
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01_ Hybrid Mate Tg3.indd 4 20/08/2021 5:24 PM