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Matematik   Tingkatan 3  Bab 1
                  8.  (a)  Padankan  setiap  berikut  dengan  bentuk      (b)  Isikan  petak  kosong  di  ruang  jawapan
                         termudah.                                             dengan nombor yang betul.
                         Match each of the following with its simplest form.   Fill in the boxes in the answer space with correct numbers.
                                                 [3 markah/ 3 marks]                                  [2 markah / 2 marks]
                         Jawapan/ Answer :                                     Jawapan/ Answer :
                                                                                               1 2
                                                                                             12
                                                                                     3
                                                                                2
                                                                                       2
                          (p  × p )                      p –2                  8  = (2  )  = (2  )
                            2
                               3 2
                                                                               8  = (8)           8   = (2 )
                                                                                                   2
                                                                                2
                                                                                     2
                                                                                                        3 2
                                                          3                          3
                                                         p 2                     = (2  )              = 2
                                                                                                        6
                                                                                       2
                                                                                                           1 2
                                                                                                         12
                            p
                              4
                           1 2 2                         p 2                                          = (2  )
                            p
                              5
                                                                       Bahagian       C
                                                         p 10
                                                                        10.  (a)  Selesaikan setiap persamaan yang berikut.
                            4
                           (√p )                         p 12                  Solve each of the following equations.
                              3 2
                                                                                                       [1 markah/ 1 mark]
                                                                               (i)  3  × 3  = 3
                                                                                    2
                                                                                            4
                                                                                        x
                                                                               (ii)  2  × 4  = 32     [2 markah/ 2 marks]
                                                                                    y
                                                                                        2
                     (b)  Tandakan  (✓)  jika  pernyataan  di  ruang           Jawapan/ Answer :
                                                                                    2
                                                                                            4
                                                                                        x
                         jawapan adalah benar dan (7) jika tidak.              (i)   3  × 3   = 3
                                                                                      2 + x
                                                                                            4
                         Mark (✓) if the statement in the answer space is true and        3    = 3
                         (7) if not.                                                 2 + x  = 4
                                                 [1 markah/ 1 mark]                     x  = 2
                         Jawapan/ Answer :                                     (ii)     2  × 4  = 32
                                                                                            2
                                                                                        y
                                                                                                5
                          Nombor  dalam  tatatanda  indeks  boleh                     2  × (2 )  = 2
                                                                                       y
                                                                                           2 2
                          ditulis  sebagai  a   dengan  a  dikenali                    2  × 2  = 2 5
                                                                                            4
                                                                                        y
                                           n
                                                                                                5
                          sebagai indeks.                                                2 y + 4  = 2
                          A number in index notation can be written as a  where          y + 4 = 5
                                                           n
                          a is known as index.                                              y = 1
                                                              7
                                                                          (b)  Selesaikan persamaan serentak yang berikut.
                         a ,  a  dikenali  sebagai  asas  dan  n  dikenali     Solve the following simultaneous equations.
                          n
                                                                                         x
                                                                                             y
                         sebagai indeks.                                                2  × 2   = 128
                         a is known as the base and n is known as the index.               6 x    = 36   y
                                                                                           6
                                                                                                      [4 markah/ 4 marks]
                  9.  (a)  Rajah   di   bawah   menunjukkan   satu             Jawapan/ Answer :
                         persamaan.                                                 2  × 2   = 128
                                                                                         y
                                                                                     x
                         The diagram below shows an equation.                         2 x + y   = 2
                                                                                             7
                                     p  × p  × q 4   = p q                           x + y  = 7 …… 1
                                          2
                                      3
                                                   n  –2
                                         q m                                           6 x
                                                                                           = 36   y
                                                                                       6
                         Nyatakan nilai m dan nilai n.                                6 x – 1   = (6 )
                                                                                              2 y
                         State the value of m and of n.                                x – 1  2y
                                                 [2 markah/ 2 marks]                  6    = 6
                         Jawapan/ Answer :                                           x – 1  = 2y
                          p  × p  × q 4                                             x – 2y  = 1 …… 2
                               2
                           3
                                       = p q
                                         n –2
                              q m                                              1 – 2:  y – (–2y) = 7 – 1
                                 q
                             p 3 + 2 4 – m  = p q                                            3y = 6
                                         n –2
                               p q     = p q                                                  y = 2
                                         n –2
                                5 4 – m
                                                                               Gantikan y = 2 ke dalam 1:
                         n = 5,  4 – m  = –2                                   Substitute y = 2 into 1:
                                   m  = 6                                       x + 2 = 7
                                                                                  x = 5
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