Page 22 - Ranger SPM 2022 - Additional Mathematics
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Additional Mathematics  SPM  Chapter  2 Quadratic Functions

                    HOTS   Example 2                         Solution
                   The diagram below shows a bucket in the   Volume of cylinder
                   shape of a cylinder which is fully-filled with   22     2
                                                                   21
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                   water and another container in the shape of   =   7   ×   2   × 18
                   a right prism with a rectangular base ABCD.   = 6 237 cm 3
                   The trapezium ABFE is the uniform cross
                   section  of the  right  prism.  All  the  water   Volume of water in the right prism = 6 237 cm 3
                   from the bucket is poured into the container   3   1                               Form 4
                           3                                   ×   (14 + 10)x × (5x – 27) = 6 237
                   and filled   of the container.           4   2
                           4                                              9x(5x –  27) = 6 237
                                             H   G                         x(5x –  27) = 693
                                                                         2
                                                   x cm                5x  – 27x – 693 = 0
                              14 cm          D    C
                                                                       (–27)
                                                                            2
                                E                           x =  –(–27) ± – 4(5)(–693)
                          18 cm       F      (5x – 27) cm                2(5)
                                  A  B                      x =  27 ±14 589
                    21 cm             10 cm                        10
                                                            x = –9.378 (ignored) or x = 14.78
                            22
                   Using π =   , calculate the value of x.
                            7                               Then, x  = 14.78




                                        SPM PRACTICE
                                        SPM        PRACTICE


                   Paper   1                                 5.  Find the range of values of  p if the
                                                               quadratic equation x  – 6px + p = 0 has
                                                                               2
                    1.  Given the quadratic equation           no roots.
                      x  + px = 3x – 4 has two different roots,                     2
                       2
                      find the range of values of k.         6.  The quadratic equation px  + qx + r = 0
                                                                               6
                                                                        3
                    2.  Given 7 is one of the roots of the     has roots –    and 5 . Find the values of
                                                                               7
                                                                        4
                      quadratic  equation  5(x +  k)  = 405,   p, q and r.
                                               2
                      where k is a constant. Find the values of     7.  Given  α and  β are  the  roots of the
                      k.                                       quadratic  equation 2x  – 9x + 9 = 0.
                                                                                 2
                    3.  Given a quadratic equation             Form a quadratic equation that has roots
                                                                     β
                      kx  – 3hx + 4k = 0 where  k and  h are   α   and  .
                        2
                      constants, has only one x-intercept. Find   3  3
                      h : k.
                                                             8.  (a)  Express 4x(x – 5) = (3x – 1)(x + 1)
                    4.  Given one of the roots of the equation     in general form.
                      x  + (3p – 4)x –  p  = 0, where  p is a   (b)  Hence, solve the quadratic equation
                       2
                                      2
                      constant, is negative  to another root.     and  give  the  answers correct  to  4
                      Find the  value  of the  product  of the    significant figures.
                      roots.
                                                       29




         02 Ranger Add Mathematics Tg4.indd   29                                            25/02/2022   9:10 AM
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