Page 137 - ArithBook5thEd ~ BCC
P. 137
.
11 3. 2
11 goes into 32 twice with a remainder of 10:
.2
11 3. 2
− 22
1 0
Adjoin an insignificant 0 to the dividend, bring it down, and perform another step: 11 goes into 100 9
times with a remainder of 1.
.2 9
11 3. 2 0
− 22
1 0 0
− 99
1
Now if we adjoin another insignificant 0 to the dividend, and bring it down, we see that 11 goes into 10
0 times. We record that with a 0 digit in the quotient, adjoin another insignificant 0 to the dividend,
and bring it down. Now we see that (as above) 11 goes into 100 9 times with a remainder of 1.
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