Page 167 - text book form physics kssm 2020
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Chapter 4
                                                                                                     Heat
                        Figure 4.34 shows a fi xed mass of gas being heated at constant volume. When the temperature
                  of the gas increases, average kinetic energy of its molecules increases, and the molecules move
                  with higher velocity. As the volume of gas does not change, the rate of collision of gas molecules
                  with the walls of the container increases. Force per unit area on the wall of the container also
                  increases. As such, gas pressure increases.




                                                    Key
                                                         Low velocity
                                                         High velocity








                                                     Temperature increases








                                       Figure 4.34 Fixed mass of gas heated at constant volume

                     Example 1

                    Gas in a closed steel cylinder has a pressure of 180 kPa at a temperature of 25°C. What is the
                    gas pressure when the cylinder is heated to a temperature of 52°C?
                      Solution:

                                                     14243
                                                        1
                     Step                             P  = 180 kPa
                                                      P  = Final pressure of air
                                                        2
                     List the given information in    T  = (25 + 273) = 298 K
                                                        1
                     symbols.                         T  = (52 + 273) = 325 K
                                                        2
                                                     14243 P  P
                     Step                             Volume of gas is constant.
                     Identify and write down the      Gay-Lussac’s Law formula is used.
                     formula used.                    T 1 1  =  T 2 2


                                                     14243    180 × 325
                     Step                               180   =   P 2
                     Substitute numerical values into   298   325
                     the formula and perform the       P  =
                                                                 298
                     calculations.                        2  = 196.3 kPa




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                   4.4.4                                                                            161
                   4.4.4
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