Page 35 - text book form physics kssm 2020

Chapter 2 Force and Motion I

Solution:

(a) Distance = Length of route covered
= AB + BC
= 100 m + 20 m
= 120 m
(b) Displacement = Distance between initial position and final position in a specific direction
= AB + BC
= (100 m) + (–20 m)
= 80 m (to the right)

Distance travelled
(c) Speed =
Time taken
120 m
=
20 s
= 6 m s –1

Displacement
(d) Velocity =
Time taken
80 m
=
20 s
–1
= 4 m s (to the right)

Example 2
Muthu moves from O to B along the route OAB as shown in Muthu
Figure 2.7. The time taken is 15 s. 5 m A
Determine the O
(a) distance
(b) displacement
(c) speed 13 m 12 m
(d) velocity
of Muthu’s motion.
Solution: B
Figure 2.7
(a) Distance = OA + AB
= 5 m + 12 m
= 17 m
(b) Displacement = Shortest straight line distance from O to B
= OB

2
= 5 + 12 2
= 13 m (in the direction of OB)

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2.1.2
2.1.2 29