Page 47 - text book form physics kssm 2020
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Chapter 2  Force and Motion I

                  Interpreting and Sketching Graphs
                  Interpreting displacement-time graphs can help to sketch velocity-time graphs and vice versa.
                  Velocity-time graphs can also be interpreted into acceleration-time graphs and vice versa.
                  The skill in interpreting and sketching graphs is important to solve linear motion problems.
                  Study the examples given.

                    Example 1

                    Figure 2.24 shows the displacement-time graph of an object in linear motion.

                                       Displacement, s / m

                                      10
                                       9
                                       8
                                       7
                                       6
                                       5
                                       4
                                       3
                                       2
                                       1
                                       0                                     Time, t / s
                                            2  4  6  8  10 12 14 16 18 20

                                                        Figure 2.24

                    (a) Determine the velocity of the object at each stage of its motion.
                    (b) Interpret the displacement-time graph in Figure 2.24 to sketch a velocity-time graph.

                     Solution:
                     Solution:



                    (a) Velocity = Gradient of              (b) Velocity-time graph
                                 displacement-time graph       Velocity, v / m s –1
                                                             1.0
                                    Table 2.3
                                            6 – 0
                                        v  =
                        0 s to 6 s       1  6 – 0
                                         = 1 m s –1
                                                             0.5
                                            6 – 6
                                        v  =
                        6 s to 12 s      2  12 – 6
                                         = 0 m s –1

                                            10 – 6                                            Time, t / s
                                        v  =                  0
                        12 s to 20 s     3  20 – 12               2  4  6  8 10 12 14 16 18 20
                                         = 0.5 m s –1
                                                                            Figure 2.25


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