Page 56 - text book form physics kssm 2020
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Solving Problems Related to Free Falling Objects

                      Objects thrown vertically upwards or released and falls
                 downwards experience gravitational acceleration, g. Therefore,   Object thrown  Assumption:
                 the equations of linear motion below can be applied to free   upwards      Motion in the
                 falling objects.                                                           positive direction

                                              1
                          v = u + gt   s = ut +  gt  2  v  = u  + 2gs
                                                        2
                                                            2
                                              2                                                 Object
                      In solving problems, our assumptions are upward motion
                 is motion in the positive direction and downward motion is                 Assumption:
                 motion in the negative direction as shown in Figure 2.41.    Object released   Motion in the
                                                                              downwards
                                                                                            negative direction



                                                                           Figure 2.41 Assumption of direction
                                                                           of an object’s vertical motion


                   Example 1
                                                                                SMART
                  Amirah threw a ball vertically upwards with an initial        SMART      INFO
                                  –1
                  velocity of 10 m s . Calculate the:
                  (a)  time for the ball to achieve maximum height           Ball moves upwards, u is
                  (b)  maximum height that can be reached by the ball        positive but g is negative.
                                                 –2
                  Ignore air resistance. [g = 9.81 m s ]
                   Solution:

                  (a)   Step                           Initial velocity , u = 10 m s –1
                                                       Final velocity at maximum height, v = 0 m s –1
                       List the given information in                           –2
                       symbols.                        Acceleration, g = –9.81 m s
                                                      123
                       Step
                                                       v = u + gt
                       Identify and write down the
                       formula used.
                                                      123
                       Step                            0 = 10 – 9.81t           SMART      INFO
                                                                                SMART
                       Substitute numerical values into   123 t =   10
                       the formula and perform the         9.81                              1  2
                       calculations.                     =  1.02 s           The equation s = ut +   gt
                                                                                             2
                                                                             can also be used.
                                                                                   1
                  (b)  v  = u  + 2gs                                          s = ut +   gt  2
                            2
                        2
                                                                                   2
                                                                                        1
                       0 = 10  + 2(–9.81)s                                     = 10(1.02) +  (–9.81)(1.02) 2
                             2
                             10 2                                              = 5.10 m  2
                       s =
                           2 × 9.81
                            = 5.10 m
                  50
                  50                                                                        2.3.2  2.3.3
                                                                                                   2.3.3
                                                                                            2.3.2
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